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anonymous
 5 years ago
Solve the separable differential equation dy/dx=(x10)e^(y), given the initial conditions y(2)=ln(2), to find y(0)
anonymous
 5 years ago
Solve the separable differential equation dy/dx=(x10)e^(y), given the initial conditions y(2)=ln(2), to find y(0)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wouldn't you jut use implicit differentiation and then substitute?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok first you find a diff of y=ln(x), and replace in the equation, is most easy, sorry i dont have a good english

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[dy = (x10)dx*e^(x)\] \[e^y*dy = (x10)dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then integrate both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure I understand. In my answer I used partial derivatives, but I'm not sure how I got the answer when I did it previously...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fxx(x,y)=6x and fyy(x,y)=2 and fxy(x,y)=6, and I got D=6x(2)(6)^2=12x36 which is the answer... but I don't know where I got 6x(2)(6)^2 from previously.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^Sorry, the above post was meant for a different question.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Frayar22, do you mean differentiate y=ln(x) ... y=1/x? I don't get it :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry , i have a mistake sorry forgive all i say (sorry for my bad englsih)
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