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anonymous

  • 5 years ago

Solve the separable differential equation dy/dx=(x-10)e^(-y), given the initial conditions y(2)=ln(2), to find y(0)

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  1. anonymous
    • 5 years ago
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    wouldn't you jut use implicit differentiation and then substitute?

  2. anonymous
    • 5 years ago
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    ok first you find a diff of y=ln(x), and replace in the equation, is most easy, sorry i dont have a good english

  3. anonymous
    • 5 years ago
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    \[dy = (x-10)dx*e^-(x)\] \[e^y*dy = (x-10)dx\]

  4. anonymous
    • 5 years ago
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    then integrate both sides

  5. anonymous
    • 5 years ago
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    I'm not sure I understand. In my answer I used partial derivatives, but I'm not sure how I got the answer when I did it previously...

  6. anonymous
    • 5 years ago
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    fxx(x,y)=6x and fyy(x,y)=2 and fxy(x,y)=-6, and I got D=6x(2)-(-6)^2=12x-36 which is the answer... but I don't know where I got 6x(2)-(-6)^2 from previously.

  7. anonymous
    • 5 years ago
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    ^Sorry, the above post was meant for a different question.

  8. anonymous
    • 5 years ago
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    Frayar22, do you mean differentiate y=ln(x) ... y=1/x? I don't get it :(

  9. anonymous
    • 5 years ago
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    sorry , i have a mistake sorry forgive all i say (sorry for my bad englsih)

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