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anonymous
 5 years ago
When t>1 the number of people coming daily to a tourist attraction gradually grows according to f(t)=(t)^0.5+5/(t)^0.5 hundreds after t days. What is the growth rate when t=9 days?
anonymous
 5 years ago
When t>1 the number of people coming daily to a tourist attraction gradually grows according to f(t)=(t)^0.5+5/(t)^0.5 hundreds after t days. What is the growth rate when t=9 days?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just substitute 9 for t in your equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you want the answer i canc alculate it its not too hard of a calculation., your problem takes form f(9) = 9 ^0.5 + 5/(9)^0.5 which becomes 3+5/3 which then if u simplify the fractions it becomes 14/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you have problems like that, its basically asking for an exact value, because it is giving you an instantaneous moment, i.e. 9 days.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for others viewing this, if i'm wrong plz let me know.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does the function f tell you how many people are present at a given t or the rate at which they increase from day to day?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this seems more like a simple calculus problem than algebra...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I believe it tells how many people are present at a given t.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0time being replaced by 9 days no?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0JS, the answer is 7.41 people/day.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then find \[f^\prime(9)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why would you differentiate the equation to obtain growth?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Perhaps I am differentiating the function incorrectly.. hmm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don't think it has to do with differentiation but that's my opinion.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0square root of 9=3 l mean 9^0.5=3 put 3 all instead of 9^0.5 result can be 14/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's wat i thought as well.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if the function tells you how many people are at the attraction at a given day then the rate at which the number of people is growing on a given day would be given by the derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0JS Why do you think diferentiation for this question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if u differentiate the equation though, the proper differed equation is:\[0.5t ^{0.5}  2.5 t ^{1.5}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i didn't think it was differentiation., but in the case that i am wrong thats the differed equation. cuz when u substitute 9 in differed equation the value is wrong.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright, thank you anyway!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0SLİM555 lm so sory l made a mistake your question asks rate that means tangent we have to take firt derivative of f(t) f'(t)=0.5t−0.5−2.5t−1.5
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