anonymous
  • anonymous
When t>1 the number of people coming daily to a tourist attraction gradually grows according to f(t)=(t)^0.5+5/(t)^0.5 hundreds after t days. What is the growth rate when t=9 days?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
just substitute 9 for t in your equation
anonymous
  • anonymous
if you want the answer i canc alculate it its not too hard of a calculation., your problem takes form f(9) = 9 ^0.5 + 5/(9)^0.5 which becomes 3+5/3 which then if u simplify the fractions it becomes 14/3
anonymous
  • anonymous
when you have problems like that, its basically asking for an exact value, because it is giving you an instantaneous moment, i.e. 9 days.

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More answers

anonymous
  • anonymous
for others viewing this, if i'm wrong plz let me know.
anonymous
  • anonymous
does the function f tell you how many people are present at a given t or the rate at which they increase from day to day?
anonymous
  • anonymous
this seems more like a simple calculus problem than algebra...
anonymous
  • anonymous
I believe it tells how many people are present at a given t.
anonymous
  • anonymous
time being replaced by 9 days no?
anonymous
  • anonymous
JS, the answer is 7.41 people/day.
anonymous
  • anonymous
then find \[f^\prime(9)\]
anonymous
  • anonymous
why would you differentiate the equation to obtain growth?
anonymous
  • anonymous
Perhaps I am differentiating the function incorrectly.. hmm
anonymous
  • anonymous
i don't think it has to do with differentiation but that's my opinion.
anonymous
  • anonymous
square root of 9=3 l mean 9^0.5=3 put 3 all instead of 9^0.5 result can be 14/3
anonymous
  • anonymous
that's wat i thought as well.
anonymous
  • anonymous
if the function tells you how many people are at the attraction at a given day then the rate at which the number of people is growing on a given day would be given by the derivative
anonymous
  • anonymous
JS Why do you think diferentiation for this question
anonymous
  • anonymous
if u differentiate the equation though, the proper differed equation is:\[0.5t ^{-0.5} - 2.5 t ^{-1.5}\]
anonymous
  • anonymous
i didn't think it was differentiation., but in the case that i am wrong thats the differed equation. cuz when u substitute 9 in differed equation the value is wrong.
anonymous
  • anonymous
Alright, thank you anyway!
anonymous
  • anonymous
SLİM555 lm so sory l made a mistake your question asks rate that means tangent we have to take firt derivative of f(t) f'(t)=0.5t−0.5−2.5t−1.5
anonymous
  • anonymous
exactly

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