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anonymous
 5 years ago
so here is a question about absolute convergence see if it is right
anonymous
 5 years ago
so here is a question about absolute convergence see if it is right

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/updates/attachments/4da96792d6938b0b4499a54davnis1302948850351calculus.JPG

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got it converges over the intervale 3<x<3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does this stem from a previous question? what is the power series?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the link i posted is the question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/updates/attachments/4da96792d6938b0b4499a54davnis1302948850351calculus.JPG

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/updates/attachments/4da96792d6938b0b4499a54davnis1302948850351calculus.JPG

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay it was not showing up , one sec I'll take a look

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks :) i think i am doing it wrong though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, i am getting different numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what did you get though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have not check the end points yet but I got 8<x<12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you do it though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I used the ratio test

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{(x5)^{(n+1)}}{(n+1)2^{(n+1)}}\frac{n2^n}{(x5)^n}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0simplifying\[=(x5)\frac{n}{2(n+1)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and \[lim_{n\rightarrow\infty}(x5)\frac{n}{2(n+1)}\]\[=(x5)\frac{1}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that is what I got

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1<\frac{1}{2}(x5)<1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it does not converge absolutely at x=3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0although it does converge at x=3, just not absolutely

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it does not converge at all at x=7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm yes so (3,7) or [3.7)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, it depends it converges absolutely on (3,7) and conditionally at 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If the question asks what is the interval of absolute convergence, I would answer (3,7) because clearly the series that arises when x=3 converges conditionally

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0by the alternating series test

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay just looked at the question again My answer would be : converges absolutely on (3,7), conditionally at x=3 and diverges at x=7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm yes so (3,7) or [3.7)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The question asked "for what values of x does the series, converge absolutely? converge conditionally?, diverge? So you must address all three questions which my answer above does
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