anonymous
  • anonymous
8= 5+ 2log(x/4)....solve for x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
subtract 5 from both sides of the equation and post what you got.
anonymous
  • anonymous
3=2log(x/4)
anonymous
  • anonymous
divide 2 on both sides and post what you got.

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anonymous
  • anonymous
3/2=log(x/4)
anonymous
  • anonymous
now take inverse log on both sides.
anonymous
  • anonymous
i dont know how
anonymous
  • anonymous
okay, \[\log_{a}x =y \rightarrow x = y^{a} \]
anonymous
  • anonymous
so x=3/2^4
anonymous
  • anonymous
no, the natural log, ln is generally to the base e, that is, \[\ln =\log_{e} \] whereas when you see log in a problem, it generally to the base 10. that is, \[\log_{} = \log_{10} \]
anonymous
  • anonymous
im confused on what it would look like
anonymous
  • anonymous
so, if you know that \[\log_{a} x=y→x=y^{a}\] and
anonymous
  • anonymous
\[\log_{10}(x/4) = 3/2 \rightarrow x/4 = ?\]
anonymous
  • anonymous
3/2^10
anonymous
  • anonymous
whoops my mistake. \[\log_{a}x = y \rightarrow x = a ^{y} \]
anonymous
  • anonymous
ok got it thanks
anonymous
  • anonymous
you are welcome.
anonymous
  • anonymous
for example, \[\log_{10}1000 = 3 \] why? because \[10^{3} = 1000\]
anonymous
  • anonymous
i have another
anonymous
  • anonymous
similarly \[\log_{10}64 = 1.80 \] why? because \[10^{1.8} = 64\]
anonymous
  • anonymous
do you understand the concept of logarithms?
anonymous
  • anonymous
yes i do property of logs
anonymous
  • anonymous
not the properties, do you understand the fundamental concept of logs?
anonymous
  • anonymous
log base 5 (3x+10) -3 log base 5 (4)=2.......yes i do!
anonymous
  • anonymous
okay great!
anonymous
  • anonymous
could u help me with that problem
anonymous
  • anonymous
log a + log b = ?
anonymous
  • anonymous
log a time b
anonymous
  • anonymous
and log a - log b = ?
anonymous
  • anonymous
divide
anonymous
  • anonymous
a log b?
anonymous
  • anonymous
logb^a
anonymous
  • anonymous
ok so what is 3 log 4?
anonymous
  • anonymous
64
anonymous
  • anonymous
what?
anonymous
  • anonymous
are you sure?
anonymous
  • anonymous
log64
anonymous
  • anonymous
okay good so what is log(3x+10)-log64?
anonymous
  • anonymous
log has a base of 5 on both
anonymous
  • anonymous
\[\log_{5} \]
anonymous
  • anonymous
yes.
anonymous
  • anonymous
so what?
anonymous
  • anonymous
im confused from there
anonymous
  • anonymous
log(3x+10)/64
anonymous
  • anonymous
okay, when you say \[\log A+\log B = \log(A*B) \], what you really mean is \[\log_{x}A+\log_{x}B = \log_{x}AB \]
anonymous
  • anonymous
well division
anonymous
  • anonymous
so only if your bases are the same, you can perform logarthmic arithmetic.
anonymous
  • anonymous
yea
anonymous
  • anonymous
so your equation now becomes \[\log_{5}((3x+10)/64 ) = 2\]
anonymous
  • anonymous
we know that \[\log_{a}x = y \rightarrow x = a ^{y}\]
anonymous
  • anonymous
ok
anonymous
  • anonymous
so what is 3x+10/64 = ?
anonymous
  • anonymous
25
anonymous
  • anonymous
so 3x+10 = ?
anonymous
  • anonymous
ok got it thank u again
anonymous
  • anonymous
you are welcome.
anonymous
  • anonymous
ok so i am stuck on another i am at x+4(x-1)=36

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