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anonymous
 5 years ago
8= 5+ 2log(x/4)....solve for x
anonymous
 5 years ago
8= 5+ 2log(x/4)....solve for x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0subtract 5 from both sides of the equation and post what you got.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0divide 2 on both sides and post what you got.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now take inverse log on both sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, \[\log_{a}x =y \rightarrow x = y^{a} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, the natural log, ln is generally to the base e, that is, \[\ln =\log_{e} \] whereas when you see log in a problem, it generally to the base 10. that is, \[\log_{} = \log_{10} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im confused on what it would look like

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, if you know that \[\log_{a} x=y→x=y^{a}\] and

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\log_{10}(x/4) = 3/2 \rightarrow x/4 = ?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whoops my mistake. \[\log_{a}x = y \rightarrow x = a ^{y} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for example, \[\log_{10}1000 = 3 \] why? because \[10^{3} = 1000\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0similarly \[\log_{10}64 = 1.80 \] why? because \[10^{1.8} = 64\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you understand the concept of logarithms?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i do property of logs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not the properties, do you understand the fundamental concept of logs?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0log base 5 (3x+10) 3 log base 5 (4)=2.......yes i do!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0could u help me with that problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and log a  log b = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so what is 3 log 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay good so what is log(3x+10)log64?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0log has a base of 5 on both

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im confused from there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, when you say \[\log A+\log B = \log(A*B) \], what you really mean is \[\log_{x}A+\log_{x}B = \log_{x}AB \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so only if your bases are the same, you can perform logarthmic arithmetic.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so your equation now becomes \[\log_{5}((3x+10)/64 ) = 2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we know that \[\log_{a}x = y \rightarrow x = a ^{y}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what is 3x+10/64 = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok got it thank u again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so i am stuck on another i am at x+4(x1)=36
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