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anonymous

  • 5 years ago

8= 5+ 2log(x/4)....solve for x

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  1. anonymous
    • 5 years ago
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    subtract 5 from both sides of the equation and post what you got.

  2. anonymous
    • 5 years ago
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    3=2log(x/4)

  3. anonymous
    • 5 years ago
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    divide 2 on both sides and post what you got.

  4. anonymous
    • 5 years ago
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    3/2=log(x/4)

  5. anonymous
    • 5 years ago
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    now take inverse log on both sides.

  6. anonymous
    • 5 years ago
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    i dont know how

  7. anonymous
    • 5 years ago
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    okay, \[\log_{a}x =y \rightarrow x = y^{a} \]

  8. anonymous
    • 5 years ago
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    so x=3/2^4

  9. anonymous
    • 5 years ago
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    no, the natural log, ln is generally to the base e, that is, \[\ln =\log_{e} \] whereas when you see log in a problem, it generally to the base 10. that is, \[\log_{} = \log_{10} \]

  10. anonymous
    • 5 years ago
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    im confused on what it would look like

  11. anonymous
    • 5 years ago
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    so, if you know that \[\log_{a} x=y→x=y^{a}\] and

  12. anonymous
    • 5 years ago
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    \[\log_{10}(x/4) = 3/2 \rightarrow x/4 = ?\]

  13. anonymous
    • 5 years ago
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    3/2^10

  14. anonymous
    • 5 years ago
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    whoops my mistake. \[\log_{a}x = y \rightarrow x = a ^{y} \]

  15. anonymous
    • 5 years ago
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    ok got it thanks

  16. anonymous
    • 5 years ago
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    you are welcome.

  17. anonymous
    • 5 years ago
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    for example, \[\log_{10}1000 = 3 \] why? because \[10^{3} = 1000\]

  18. anonymous
    • 5 years ago
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    i have another

  19. anonymous
    • 5 years ago
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    similarly \[\log_{10}64 = 1.80 \] why? because \[10^{1.8} = 64\]

  20. anonymous
    • 5 years ago
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    do you understand the concept of logarithms?

  21. anonymous
    • 5 years ago
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    yes i do property of logs

  22. anonymous
    • 5 years ago
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    not the properties, do you understand the fundamental concept of logs?

  23. anonymous
    • 5 years ago
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    log base 5 (3x+10) -3 log base 5 (4)=2.......yes i do!

  24. anonymous
    • 5 years ago
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    okay great!

  25. anonymous
    • 5 years ago
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    could u help me with that problem

  26. anonymous
    • 5 years ago
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    log a + log b = ?

  27. anonymous
    • 5 years ago
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    log a time b

  28. anonymous
    • 5 years ago
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    and log a - log b = ?

  29. anonymous
    • 5 years ago
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    divide

  30. anonymous
    • 5 years ago
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    a log b?

  31. anonymous
    • 5 years ago
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    logb^a

  32. anonymous
    • 5 years ago
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    ok so what is 3 log 4?

  33. anonymous
    • 5 years ago
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    64

  34. anonymous
    • 5 years ago
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    what?

  35. anonymous
    • 5 years ago
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    are you sure?

  36. anonymous
    • 5 years ago
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    log64

  37. anonymous
    • 5 years ago
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    okay good so what is log(3x+10)-log64?

  38. anonymous
    • 5 years ago
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    log has a base of 5 on both

  39. anonymous
    • 5 years ago
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    \[\log_{5} \]

  40. anonymous
    • 5 years ago
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    yes.

  41. anonymous
    • 5 years ago
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    so what?

  42. anonymous
    • 5 years ago
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    im confused from there

  43. anonymous
    • 5 years ago
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    log(3x+10)/64

  44. anonymous
    • 5 years ago
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    okay, when you say \[\log A+\log B = \log(A*B) \], what you really mean is \[\log_{x}A+\log_{x}B = \log_{x}AB \]

  45. anonymous
    • 5 years ago
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    well division

  46. anonymous
    • 5 years ago
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    so only if your bases are the same, you can perform logarthmic arithmetic.

  47. anonymous
    • 5 years ago
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    yea

  48. anonymous
    • 5 years ago
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    so your equation now becomes \[\log_{5}((3x+10)/64 ) = 2\]

  49. anonymous
    • 5 years ago
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    we know that \[\log_{a}x = y \rightarrow x = a ^{y}\]

  50. anonymous
    • 5 years ago
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    ok

  51. anonymous
    • 5 years ago
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    so what is 3x+10/64 = ?

  52. anonymous
    • 5 years ago
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    25

  53. anonymous
    • 5 years ago
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    so 3x+10 = ?

  54. anonymous
    • 5 years ago
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    ok got it thank u again

  55. anonymous
    • 5 years ago
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    you are welcome.

  56. anonymous
    • 5 years ago
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    ok so i am stuck on another i am at x+4(x-1)=36

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