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anonymous
 5 years ago
graph the parabola. showt the zeros and the maxima or minima.
y=x^26x+8
anonymous
 5 years ago
graph the parabola. showt the zeros and the maxima or minima. y=x^26x+8

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you find the zeros when you solve x^2  6x + 8 = 0 you need the first derivative for maxima and minima the same thing... first derivative = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is true if this is a calculus question. However the question may be answered without calculus The max or min of a parabola is the vertex, the axis of symmetry is given by \[x=\frac{b}{2a}\] for the parabola in the form \[y=ax^2+bx+c\] get the vertex by evaluating for y at this x value moreover this parabola will have a min as the coefficient of x^2 is positive

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A plot of the parabola is attached.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0robtobey howd you get that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have to show work :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The plot was generated by Mathematica 8 with this statement: Plot[x^26x+8,{x,1,5}] You might Google "how to plot a parabola" I have never plotted a curve without Mathematica for years.
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