graph the parabola. showt the zeros and the maxima or minima. y=x^2-6x+8

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graph the parabola. showt the zeros and the maxima or minima. y=x^2-6x+8

Mathematics
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you find the zeros when you solve x^2 - 6x + 8 = 0 you need the first derivative for maxima and minima the same thing... first derivative = 0
that is true if this is a calculus question. However the question may be answered without calculus The max or min of a parabola is the vertex, the axis of symmetry is given by \[x=\frac{-b}{2a}\] for the parabola in the form \[y=ax^2+bx+c\] get the vertex by evaluating for y at this x value moreover this parabola will have a min as the coefficient of x^2 is positive
A plot of the parabola is attached.
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thanks yalll
robtobey howd you get that?
i have to show work :/
The plot was generated by Mathematica 8 with this statement: Plot[x^2-6x+8,{x,1,5}] You might Google "how to plot a parabola" I have never plotted a curve without Mathematica for years.

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