## anonymous 5 years ago graph the parabola. showt the zeros and the maxima or minima. y=x^2-6x+8

1. anonymous

you find the zeros when you solve x^2 - 6x + 8 = 0 you need the first derivative for maxima and minima the same thing... first derivative = 0

2. anonymous

that is true if this is a calculus question. However the question may be answered without calculus The max or min of a parabola is the vertex, the axis of symmetry is given by $x=\frac{-b}{2a}$ for the parabola in the form $y=ax^2+bx+c$ get the vertex by evaluating for y at this x value moreover this parabola will have a min as the coefficient of x^2 is positive

3. anonymous

A plot of the parabola is attached.

4. anonymous

thanks yalll

5. anonymous

robtobey howd you get that?

6. anonymous

i have to show work :/

7. anonymous

The plot was generated by Mathematica 8 with this statement: Plot[x^2-6x+8,{x,1,5}] You might Google "how to plot a parabola" I have never plotted a curve without Mathematica for years.