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anonymous
 5 years ago
how do you do this integral:
∫(t^2)sin(t^3+t^4)√(2t+9t^4+16t^6 )dt
from 0 to 5?
anonymous
 5 years ago
how do you do this integral: ∫(t^2)sin(t^3+t^4)√(2t+9t^4+16t^6 )dt from 0 to 5?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That problem is insane

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can't use calculator either

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i typed it into wolframalpha.com it solved the problem but it didnt give the result

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I get  12.01 but after the 01 the number goes even further than that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know if thats the right answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0unless there is another way around it. original problem is fine the line integran \[\int\limits_{}^{} xsin(y+z)ds

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops lemme do that again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0find the line integral: \[\int\limits_{}^{} xsin(y+z)ds\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where x = t^2 y= t^3 z=t^4 \[0\le t \le5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer should be around 15 too

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what the professor told us.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow not much of a professor lol I thought professor knew everything

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well he told us he wanted us to solve it. And that the answer was around 15 to kinda help us i guess. But no clue where to even begin solving that integral

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow i still dont know where to start

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think you can use integration by parts here. http://en.wikipedia.org/wiki/Integration_by_parts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0umm.. not sure how i would approach it with that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, I don't remember the procedure now. I just know that these type of integrations can be solved using integration by parts. I think the wikipedia page has the description of how to do it. Sorry I can't be of more help.
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