Find the points on the given curve where the tangent line is horizontal or vertical. r = 3cos(theta)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Find the points on the given curve where the tangent line is horizontal or vertical. r = 3cos(theta)

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Use y=rsin(theta) x=rcos(theta) Take dy/dx .. take it from here?
yup got it thanks
YEAAH!

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

well i actually have to do it but haha your not completely right atm lemme see
actually don't you use the polar curve formula of dy/dx = rcos(theta) + sin(theta) (dr/d(theta)) / -rsin(theta)+cos(theta) (dr/d(theta))? then just set top = 0 or the bottom = 0?
So when your dx=0 you have a vertical tangent line. Actually for this equations there are alot of points where it should be vertical and the horizontal points aren't quite as easy because you have to solve something like 3(cos^2(theta)-sin^2(theta))=0
yep thats exactly what you do, the formula you typed is just the product rule for derivatives
actually not quite
alrighty. easy enough. thanks =)
yep :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question