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anonymous

  • 5 years ago

simply. assume all variables represent positive real numbers (sqrt = quare root): 1.) sqrt. 96x^2 y 2.) ^4 sqrt. 16a^4 3.) ^3 sqrt. 64x^4 y^5

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  1. anonymous
    • 5 years ago
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    please help, i am taking an exam & dont understand it :(

  2. anonymous
    • 5 years ago
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    i dont understand what you are supposed to find out.

  3. anonymous
    • 5 years ago
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    like whats it on? on my exam it just says to simplify

  4. anonymous
    • 5 years ago
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    its 3 different problems

  5. anonymous
    • 5 years ago
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    \[\sqrt{96x ^{2}y}=\sqrt{16*6x ^{2}y}=4x \sqrt{6y}\]

  6. anonymous
    • 5 years ago
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    \[\sqrt[4]{16a ^{4}}=\sqrt[4]{(2a)^{4}} = 2a\]

  7. anonymous
    • 5 years ago
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    \[\sqrt[3]{64 x ^{4}y ^{5}}=\sqrt[3]{(4xy)^{3}xy ^{2}}=4xy \sqrt[3]{xy ^{2}}\]

  8. anonymous
    • 5 years ago
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    THANK YOU SO MUCH !

  9. anonymous
    • 5 years ago
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    can you help me out please with a couple more problems?

  10. anonymous
    • 5 years ago
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    no, I can't do your problems for you. I have shown you how to do these problems. You can do the rest on your own if you apply the same logic. if you have doubts, feel free to ask and I will clarify.

  11. anonymous
    • 5 years ago
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    aw okay , thanks though. but for adding and subtracting them with others would they need the same sqrt inside ?

  12. anonymous
    • 5 years ago
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    give me an example.

  13. anonymous
    • 5 years ago
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    [2 sqrt. 128] + [5 sqrt. 32] + [2 sqrt.200]

  14. anonymous
    • 5 years ago
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    sqrt3 is a number. So if you had 3sqrt 3 +5sqrt3 sqrt 4, you can factor out sqrt3 as if it was a number so it would become sqrt 3 (3+5sqrt4)

  15. anonymous
    • 5 years ago
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    you mean [2 sqrt.200] as sqrt.3 ?

  16. anonymous
    • 5 years ago
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    no , I was giving an example of my own. In your problem you can express sqrt 200 as sqrt 8 sqrt 25. you can express sqrt 32 as sqrt4 sqrt 8. you can express sqrt 128 as sqrt 8 sqrt 16

  17. anonymous
    • 5 years ago
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    how do you know how to express it ?

  18. anonymous
    • 5 years ago
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    you see what is the highest common factor between 200, 32 and 128 and factor it out.

  19. anonymous
    • 5 years ago
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    all 3 have to have the same in common ?

  20. anonymous
    • 5 years ago
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    which would be 8 ?

  21. anonymous
    • 5 years ago
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    yup.

  22. anonymous
    • 5 years ago
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    so answer would be 9 sqrt.8 ?

  23. anonymous
    • 5 years ago
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    the numbers add up to 9

  24. anonymous
    • 5 years ago
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    nope.

  25. anonymous
    • 5 years ago
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    2 + 5 + 2 = 9 ?

  26. anonymous
    • 5 years ago
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    it does

  27. anonymous
    • 5 years ago
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    so if we have the same sqrt. already than just add the numbers which give 9

  28. anonymous
    • 5 years ago
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    yes, but 2 sqrt 200 = 2 sqrt 5 sqrt 8 = 2*5 sqrt 8= 10sqrt8

  29. anonymous
    • 5 years ago
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    sorry 2*sqrt 200 = 2*sqrt 25*sqrt 8 = 2*5*sqrt8 = 10sqrt8

  30. anonymous
    • 5 years ago
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    and simplfying that would give [2 sqrt. 2] ?

  31. anonymous
    • 5 years ago
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    half of each other

  32. anonymous
    • 5 years ago
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    yes, if you want to simply it further, sqrt 8 = 2 sqrt2

  33. anonymous
    • 5 years ago
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    and to simplfy that is 1 ?

  34. anonymous
    • 5 years ago
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    simplify what is 1?

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