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anonymous
 5 years ago
simply. assume all variables represent positive real numbers (sqrt = quare root): 1.) sqrt. 96x^2 y
2.) ^4 sqrt. 16a^4
3.) ^3 sqrt. 64x^4 y^5
anonymous
 5 years ago
simply. assume all variables represent positive real numbers (sqrt = quare root): 1.) sqrt. 96x^2 y 2.) ^4 sqrt. 16a^4 3.) ^3 sqrt. 64x^4 y^5

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0please help, i am taking an exam & dont understand it :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand what you are supposed to find out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like whats it on? on my exam it just says to simplify

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its 3 different problems

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{96x ^{2}y}=\sqrt{16*6x ^{2}y}=4x \sqrt{6y}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[4]{16a ^{4}}=\sqrt[4]{(2a)^{4}} = 2a\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[3]{64 x ^{4}y ^{5}}=\sqrt[3]{(4xy)^{3}xy ^{2}}=4xy \sqrt[3]{xy ^{2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me out please with a couple more problems?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, I can't do your problems for you. I have shown you how to do these problems. You can do the rest on your own if you apply the same logic. if you have doubts, feel free to ask and I will clarify.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0aw okay , thanks though. but for adding and subtracting them with others would they need the same sqrt inside ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0[2 sqrt. 128] + [5 sqrt. 32] + [2 sqrt.200]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt3 is a number. So if you had 3sqrt 3 +5sqrt3 sqrt 4, you can factor out sqrt3 as if it was a number so it would become sqrt 3 (3+5sqrt4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you mean [2 sqrt.200] as sqrt.3 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no , I was giving an example of my own. In your problem you can express sqrt 200 as sqrt 8 sqrt 25. you can express sqrt 32 as sqrt4 sqrt 8. you can express sqrt 128 as sqrt 8 sqrt 16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you know how to express it ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you see what is the highest common factor between 200, 32 and 128 and factor it out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all 3 have to have the same in common ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so answer would be 9 sqrt.8 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the numbers add up to 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if we have the same sqrt. already than just add the numbers which give 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, but 2 sqrt 200 = 2 sqrt 5 sqrt 8 = 2*5 sqrt 8= 10sqrt8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry 2*sqrt 200 = 2*sqrt 25*sqrt 8 = 2*5*sqrt8 = 10sqrt8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and simplfying that would give [2 sqrt. 2] ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, if you want to simply it further, sqrt 8 = 2 sqrt2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and to simplfy that is 1 ?
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