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please help, i am taking an exam & dont understand it :(

i dont understand what you are supposed to find out.

like whats it on? on my exam it just says to simplify

its 3 different problems

\[\sqrt{96x ^{2}y}=\sqrt{16*6x ^{2}y}=4x \sqrt{6y}\]

\[\sqrt[4]{16a ^{4}}=\sqrt[4]{(2a)^{4}} = 2a\]

\[\sqrt[3]{64 x ^{4}y ^{5}}=\sqrt[3]{(4xy)^{3}xy ^{2}}=4xy \sqrt[3]{xy ^{2}}\]

THANK YOU SO MUCH !

can you help me out please with a couple more problems?

give me an example.

[2 sqrt. 128] + [5 sqrt. 32] + [2 sqrt.200]

you mean [2 sqrt.200] as sqrt.3 ?

how do you know how to express it ?

you see what is the highest common factor between 200, 32 and 128 and factor it out.

all 3 have to have the same in common ?

which would be 8 ?

yup.

so answer would be 9 sqrt.8 ?

the numbers add up to 9

nope.

2 + 5 + 2 = 9 ?

it does

so if we have the same sqrt. already than just add the numbers which give 9

yes, but 2 sqrt 200 = 2 sqrt 5 sqrt 8 = 2*5 sqrt 8= 10sqrt8

sorry 2*sqrt 200 = 2*sqrt 25*sqrt 8 = 2*5*sqrt8 = 10sqrt8

and simplfying that would give [2 sqrt. 2] ?

half of each other

yes, if you want to simply it further, sqrt 8 = 2 sqrt2

and to simplfy that is 1 ?

simplify what is 1?