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anonymous
 5 years ago
Let the reproductive rates in four successive generations of a population be 4,2,3,2. If the population has a size of 10 million individuals at the end of this fourgeneration period, how large will it be after another two generations if there is no regulation of growth? Carrying capacity is 100 million.
anonymous
 5 years ago
Let the reproductive rates in four successive generations of a population be 4,2,3,2. If the population has a size of 10 million individuals at the end of this fourgeneration period, how large will it be after another two generations if there is no regulation of growth? Carrying capacity is 100 million.

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0do you expect the pattern to continue? 4,2,3,2,2,2...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0after another 2 generation

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0ok so then after the next generation with a reproductive rate of 2 it would grow 200% to 30 million >10(1+2) = 30 Repeating this for the next generation 30(1+2) = 90 90 million is that right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take note with the carrying capacity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the rate of increase of the total population is \[dN/dt =r1n1+r2n2 = mean of the r's(N)\]

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0does n1 refer to initial population, n2 second generation and r1 is reproductive rate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let N be the total population number; N = n1 + n2.

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0is this for a differential equations class

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0get the mean of the r

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0the mean of the rates is 15/6 for all generations, how does that help? im sorry im not following or helping you :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dn2/dt=n2(r2mean of r (N)/K K is the carrying capacity

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0so dn2/dt = n2(2  15/6) / 100 mill >dn2/dt = n2/200 what is n2?

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0if we integrate both sides and solve for n2 > n2 = e^t/200

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0but the problem only refers to generations not time, so to get a number for n we need a t ??

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0do you know the answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we only have one strain n

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0ok well i gotta go, good luck hope you find someone to help you sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you very much, take care and GOD BLESS

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your a great help, thanks a lot
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