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do you expect the pattern to continue? 4,2,3,2,2,2...
after another 2 generation
ok so then after the next generation with a reproductive rate of 2 it would grow 200% to 30 million ->10(1+2) = 30 Repeating this for the next generation 30(1+2) = 90 90 million is that right?
take note with the carrying capacity
the rate of increase of the total population is \[dN/dt =r1n1+r2n2 = mean of the r's(N)\]
does n1 refer to initial population, n2 second generation and r1 is reproductive rate
Let N be the total population number; N = n1 + n2.
is this for a differential equations class
get the mean of the r
the mean of the rates is 15/6 for all generations, how does that help? im sorry im not following or helping you :(
dn2/dt=n2(r2-mean of r (N)/K K is the carrying capacity
so dn2/dt = n2(2 - 15/6) / 100 mill ->dn2/dt = -n2/200 what is n2?
if we integrate both sides and solve for n2 -> n2 = e^-t/200
but the problem only refers to generations not time, so to get a number for n we need a t ??
do you know the answer?
we only have one strain n
ok well i gotta go, good luck hope you find someone to help you sorry
thank you very much, take care and GOD BLESS
your a great help, thanks a lot