anonymous
  • anonymous
Let the reproductive rates in four successive generations of a population be 4,2,3,2. If the population has a size of 10 million individuals at the end of this four-generation period, how large will it be after another two generations if there is no regulation of growth? Carrying capacity is 100 million.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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dumbcow
  • dumbcow
do you expect the pattern to continue? 4,2,3,2,2,2...
anonymous
  • anonymous
after another 2 generation
dumbcow
  • dumbcow
ok so then after the next generation with a reproductive rate of 2 it would grow 200% to 30 million ->10(1+2) = 30 Repeating this for the next generation 30(1+2) = 90 90 million is that right?

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More answers

anonymous
  • anonymous
take note with the carrying capacity
anonymous
  • anonymous
dn1/dt=r1n1
anonymous
  • anonymous
\[dn2/dt =r2n2\]
anonymous
  • anonymous
the rate of increase of the total population is \[dN/dt =r1n1+r2n2 = mean of the r's(N)\]
dumbcow
  • dumbcow
does n1 refer to initial population, n2 second generation and r1 is reproductive rate
anonymous
  • anonymous
Let N be the total population number; N = n1 + n2.
anonymous
  • anonymous
yes
dumbcow
  • dumbcow
ok
dumbcow
  • dumbcow
is this for a differential equations class
anonymous
  • anonymous
get the mean of the r
dumbcow
  • dumbcow
the mean of the rates is 15/6 for all generations, how does that help? im sorry im not following or helping you :(
anonymous
  • anonymous
either
anonymous
  • anonymous
dn2/dt=n2(r2-mean of r (N)/K K is the carrying capacity
dumbcow
  • dumbcow
so dn2/dt = n2(2 - 15/6) / 100 mill ->dn2/dt = -n2/200 what is n2?
dumbcow
  • dumbcow
if we integrate both sides and solve for n2 -> n2 = e^-t/200
anonymous
  • anonymous
ok
dumbcow
  • dumbcow
but the problem only refers to generations not time, so to get a number for n we need a t ??
dumbcow
  • dumbcow
do you know the answer?
anonymous
  • anonymous
we only have one strain n
dumbcow
  • dumbcow
ok well i gotta go, good luck hope you find someone to help you sorry
anonymous
  • anonymous
thank you very much, take care and GOD BLESS
anonymous
  • anonymous
your a great help, thanks a lot
anonymous
  • anonymous
bye

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