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do you expect the pattern to continue?
4,2,3,2,2,2...

after another 2 generation

take note with the carrying capacity

dn1/dt=r1n1

\[dn2/dt =r2n2\]

the rate of increase of the total population is \[dN/dt =r1n1+r2n2 = mean of the r's(N)\]

does n1 refer to initial population, n2 second generation
and r1 is reproductive rate

Let N be the total population number; N = n1 + n2.

yes

ok

is this for a differential equations class

get the mean of the r

either

dn2/dt=n2(r2-mean of r (N)/K
K is the carrying capacity

so dn2/dt = n2(2 - 15/6) / 100 mill
->dn2/dt = -n2/200
what is n2?

if we integrate both sides and solve for n2
-> n2 = e^-t/200

ok

but the problem only refers to generations not time, so to get a number for n we need a t ??

do you know the answer?

we only have one strain
n

ok well i gotta go, good luck hope you find someone to help you
sorry

thank you very much, take care and GOD BLESS

your a great help, thanks a lot

bye