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you can divide 5x^2 from both the top and the bottom. Divide each coefficient in the top by 5, and subtract 2 from each exponent. (x^m / x^n = x^(m-n))
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then how would you do this one 30x^3y^2/6x^7y^2
would it be this 5X^10y^4
Just do the same thing except for both x and y. You can do it in steps. First divide the top and bottom by 6. Then divide the top and bottom by x^7, then divide the top and bottom by y^2. When you are done you might want to the negative exponent to the denominator.
No, you are close, but you are adding the exponents. You need to subtract when you are dividing.
that would make them negative correct
x^m / x^n = x^(m-n)
Also, x^(-m) = 1/x^m
Well, x^3/x^7 is x^(3-7) = x^(-4)
well then I have stupid question how do you make it where the exponents are nonnegative
x^(-m) = 1/x^m
you can turn x^(-4) to 1/(x^4)
A negative exponent just means that it is 1 over to what it would be if the exponent were positive.