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anonymous
 5 years ago
4/5(2x1)>12
anonymous
 5 years ago
4/5(2x1)>12

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you solving for x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Excuse me, is it (4/5)*(2x1)>12 or 4/[5(2x1)]>12? could you make that clearer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if it is (4/5)*(2x1)>12 then x>8; if it is 4/[5(2x1)]>12 then x>(4/5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, solving for x, and the first of the options is what it is supposed to be. :Thank you. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It told me the answer was incorrect. :( Here is a similar equation, with as far as I can get on my own: 2/3(3x6)>12 6/3x12/3>12 12(6/3x12/3)>12(12) (72/3)x(144/3)>144 I can not seem to get to the answer from here. I'm sure it's probably easy, but I need it explained in simple terms.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02/3(3x6)>12 3x6>18 3x>24 x>8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Also needing assistance with compound inequalities. Will be posting one soon. I don't just want an answer. I want someone to teach me (simply) how to solve them, stepbystep. Note: The compound inequalities have some odd fractions, so I may have to explain them differently.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Dhat: Where did the 2/3 go?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I multiplied by 3/2 on both sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, I see. Thank you. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Would you like me to post the compund inequality here, or as a new question?
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