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anonymous

  • 5 years ago

4/5(2x-1)>12

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  1. anonymous
    • 5 years ago
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    Are you solving for x?

  2. anonymous
    • 5 years ago
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    Excuse me, is it (4/5)*(2x-1)>12 or 4/[5(2x-1)]>12? could you make that clearer

  3. anonymous
    • 5 years ago
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    if it is (4/5)*(2x-1)>12 then x>8; if it is 4/[5(2x-1)]>12 then x>(4/5)

  4. anonymous
    • 5 years ago
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    Yes, solving for x, and the first of the options is what it is supposed to be. :Thank you. :)

  5. anonymous
    • 5 years ago
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    It told me the answer was incorrect. :( Here is a similar equation, with as far as I can get on my own: 2/3(3x-6)>12 6/3x-12/3>12 12(6/3x-12/3)>12(12) (72/3)x-(144/3)>144 I can not seem to get to the answer from here. I'm sure it's probably easy, but I need it explained in simple terms.

  6. anonymous
    • 5 years ago
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    2/3(3x-6)>12 3x-6>18 3x>24 x>8

  7. anonymous
    • 5 years ago
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    Also needing assistance with compound inequalities. Will be posting one soon. I don't just want an answer. I want someone to teach me (simply) how to solve them, step-by-step. Note: The compound inequalities have some odd fractions, so I may have to explain them differently.

  8. anonymous
    • 5 years ago
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    Dhat: Where did the 2/3 go?

  9. anonymous
    • 5 years ago
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    I multiplied by 3/2 on both sides.

  10. anonymous
    • 5 years ago
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    OK, I see. Thank you. :)

  11. anonymous
    • 5 years ago
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    you are welcome

  12. anonymous
    • 5 years ago
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    Would you like me to post the compund inequality here, or as a new question?

  13. anonymous
    • 5 years ago
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    new thread please

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