4/5(2x-1)>12

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Are you solving for x?
Excuse me, is it (4/5)*(2x-1)>12 or 4/[5(2x-1)]>12? could you make that clearer
if it is (4/5)*(2x-1)>12 then x>8; if it is 4/[5(2x-1)]>12 then x>(4/5)

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Other answers:

Yes, solving for x, and the first of the options is what it is supposed to be. :Thank you. :)
It told me the answer was incorrect. :( Here is a similar equation, with as far as I can get on my own: 2/3(3x-6)>12 6/3x-12/3>12 12(6/3x-12/3)>12(12) (72/3)x-(144/3)>144 I can not seem to get to the answer from here. I'm sure it's probably easy, but I need it explained in simple terms.
2/3(3x-6)>12 3x-6>18 3x>24 x>8
Also needing assistance with compound inequalities. Will be posting one soon. I don't just want an answer. I want someone to teach me (simply) how to solve them, step-by-step. Note: The compound inequalities have some odd fractions, so I may have to explain them differently.
Dhat: Where did the 2/3 go?
I multiplied by 3/2 on both sides.
OK, I see. Thank you. :)
you are welcome
Would you like me to post the compund inequality here, or as a new question?
new thread please

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