• anonymous
Consider a double-slit experiment with the spacing between the slits set at 3.50×10−3 cm, light of 630 nm, and a screen at a distance of 3.00 meters. Assume the dimensions are such that you can use the small angle approximation: sin θ ≈ tan θ ≈ θ (a) How high above the centerline from the slits to the screen is the 3rd bright fringe (counting the centerline as the 0th fringe)? (b) How high above the centerline to the screen is the 5th dark fringe? (c) How do the answers to (a) and (b) change if the measurements were made underwater (n=1.33)?
Physics
• Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Looking for something else?

Not the answer you are looking for? Search for more explanations.