is this correct? sqrt20a^2b=2asqrt5b

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is this correct? sqrt20a^2b=2asqrt5b

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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yes
thank you. just wanted to make sure!
you are welcome.

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Other answers:

If the problem expression is the following: \[\sqrt{20a^{2b}}=2a\sqrt{5b} \] then the lhs is not equal to the rhs because \[2 \sqrt{5} a^b \neq 2 \sqrt{5} a \sqrt{b} \]
thats not the expression
What is you understanding regarding the form of the original?
it is \[\sqrt{20a ^{2}b}\]
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