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anonymous

  • 5 years ago

is this correct? sqrt20a^2b=2asqrt5b

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  1. anonymous
    • 5 years ago
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    yes

  2. anonymous
    • 5 years ago
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    thank you. just wanted to make sure!

  3. anonymous
    • 5 years ago
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    you are welcome.

  4. anonymous
    • 5 years ago
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    If the problem expression is the following: \[\sqrt{20a^{2b}}=2a\sqrt{5b} \] then the lhs is not equal to the rhs because \[2 \sqrt{5} a^b \neq 2 \sqrt{5} a \sqrt{b} \]

  5. anonymous
    • 5 years ago
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    thats not the expression

  6. anonymous
    • 5 years ago
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    What is you understanding regarding the form of the original?

  7. anonymous
    • 5 years ago
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    it is \[\sqrt{20a ^{2}b}\]

  8. anonymous
    • 5 years ago
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    Thank you for responding.

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spraguer (Moderator)
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