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anonymous
 5 years ago
ok so i think i just have one more question: (30b^3+14b^2+37b+42)/(5b+4) I have a major problem understanding these equations.
anonymous
 5 years ago
ok so i think i just have one more question: (30b^3+14b^2+37b+42)/(5b+4) I have a major problem understanding these equations.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I feel for you. I hate these. Do you know polynomial long division? Did you learn it yet? I think that would be the best way to tackle it but if you haven't learned it yet then maybe they are expecting you to do it a different way. If you learned it but don't understand it, I can find a place that explains it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no the main thing we have been learning is factoring

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you certain you've written the problem correctly? This doesn't seem to simplify well.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's very mean of them. Well you can guess that (5b+4) will be one of the factors because you have to divide it somehow. So now you have to figure out what w, x, y, z, are in (5b + 4)(wx + x)(yb + z) so that it equals the numberator. However 42 isn't divisible by 4 so I am thinking too that you might have typed it wrong or that they made a mistake when they gave you that problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i double checked. the instructions just say "divide"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't think you can even do that problem easily without polynomial long division. Because if you look at my post I just made, 4*x*z must equal 42. The problem is, 42 isn't divisible by 4 so x or z must be a fraction. That's gross. I'll try to solve it and tell you if I succeed.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There must have been a mistake somewhere. I plugged it into wolfram alpha and I got this: http://www.wolframalpha.com/input/?i=factor+%2830b^3%2B14b^2%2B37b%2B42%29 (b+0.878016) (b(0.205675+1.24587 i)) (b(0.2056751.24587 i)) I don't think it is possible. You can't even factor the numerator without getting complex roots.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you anyways! i really do appreciate all the help!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No problem. If it turns out that you can do it, my apologies.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you just use long division it doesn't come out that bad. > 6b^2  2b + 9 + 6/5b+4
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