ok so i think i just have one more question: (30b^3+14b^2+37b+42)/(5b+4) I have a major problem understanding these equations.

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ok so i think i just have one more question: (30b^3+14b^2+37b+42)/(5b+4) I have a major problem understanding these equations.

Mathematics
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I feel for you. I hate these. Do you know polynomial long division? Did you learn it yet? I think that would be the best way to tackle it but if you haven't learned it yet then maybe they are expecting you to do it a different way. If you learned it but don't understand it, I can find a place that explains it.
no the main thing we have been learning is factoring
help polpak

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Are you certain you've written the problem correctly? This doesn't seem to simplify well.
That's very mean of them. Well you can guess that (5b+4) will be one of the factors because you have to divide it somehow. So now you have to figure out what w, x, y, z, are in (5b + 4)(wx + x)(yb + z) so that it equals the numberator. However 42 isn't divisible by 4 so I am thinking too that you might have typed it wrong or that they made a mistake when they gave you that problem.
yes i double checked. the instructions just say "divide"
I don't think you can even do that problem easily without polynomial long division. Because if you look at my post I just made, 4*x*z must equal 42. The problem is, 42 isn't divisible by 4 so x or z must be a fraction. That's gross. I'll try to solve it and tell you if I succeed.
thank you
There must have been a mistake somewhere. I plugged it into wolfram alpha and I got this: http://www.wolframalpha.com/input/?i=factor+%2830b^3%2B14b^2%2B37b%2B42%29 (b+0.878016) (b-(0.205675+1.24587 i)) (b-(0.205675-1.24587 i)) I don't think it is possible. You can't even factor the numerator without getting complex roots.
thank you anyways! i really do appreciate all the help!
No problem. If it turns out that you can do it, my apologies.
If you just use long division it doesn't come out that bad. -> 6b^2 - 2b + 9 + 6/5b+4

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