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anonymous
 5 years ago
how do you integrate:
∫ x/(x^2+y^2+z^2)^3/2 dx
with respect to x
anonymous
 5 years ago
how do you integrate: ∫ x/(x^2+y^2+z^2)^3/2 dx with respect to x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/2\int\limits_{?}^{?}d(x^2+y^2+z^2)/(x^2+y^2+z^2)\] 1/2ln(x^2+y^2+z^2)+C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u substitution. u=x^2+y^2+z^2 du= 2x+2y+2z dx 1/2 du=x+y+z 1/2 ∫1/u^3/2 du = 1/2(2/sqrt(u)) 1/sqrt(u) Substitute U back in and you have your answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that one makes sense. thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ugh, i sort of messed up on the du. du=2xdx, so 1/2 du= x dx.
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