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anonymous

  • 5 years ago

Solve the differential equation (x^2 + 1)y' = xy. Am having trouble separating the equation to dy/dx = g(x) h(y) format

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  1. anonymous
    • 5 years ago
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    y' is dy/dx. So divide by (x^2)+1, swing to other side.

  2. anonymous
    • 5 years ago
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    This seems to leave me me with xy dx = x^2 + 1 dy, I'm stumped as to how to get the y from the xy dx onto the dy side and vice versa with the x^2+1

  3. anonymous
    • 5 years ago
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    found a solution, thanks

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