anonymous
  • anonymous
Solve the differential equation (x^2 + 1)y' = xy. Am having trouble separating the equation to dy/dx = g(x) h(y) format
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
y' is dy/dx. So divide by (x^2)+1, swing to other side.
anonymous
  • anonymous
This seems to leave me me with xy dx = x^2 + 1 dy, I'm stumped as to how to get the y from the xy dx onto the dy side and vice versa with the x^2+1
anonymous
  • anonymous
found a solution, thanks

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