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anonymous
 5 years ago
alright, attached is the question im having trouble with now....
anonymous
 5 years ago
alright, attached is the question im having trouble with now....

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so far, i know that get the equation of the are of the rectangle, so: A=l times w [l.w] and that i should derive that equation i formed, but im having trouble at this point... not to sure on how to fine the A'. or perhaps am i on the wrong path? o:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's really hard to measure the rate of change for the area. Lets say one second has passed by. Now we have a w=1 and l=16. Area of that is 16. original area is 60 (5*12) so the area changed by 44/1sec. Now lets say half a second. w=3 l=14. The area of that is 42. The difference is now 18/0.5sec = 36/1sec. Now the lengths are changing proportional 1gain:1 loss so you can figure out how the rate is changing. Hint: if in every second you gain the same you lose how much are you changing? Again the diagonals change is not constant. try to measure the change from .5 seconds to 1 second and compare the change in length to the change rate of the area. Well is the length of the diagonals increasing? well yes but how much? next i told you the change in area is lowering.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright, thanks so much, figured it out :] i got the area decreasing at 44 cm^2/sec the perimeter is constant and the diagonals i increasing at a rate of 3cm/sec.
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