alright, attached is the question im having trouble with now....

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alright, attached is the question im having trouble with now....

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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so far, i know that get the equation of the are of the rectangle, so: A=l times w [l.w] and that i should derive that equation i formed, but im having trouble at this point... not to sure on how to fine the A'. or perhaps am i on the wrong path? o:
It's really hard to measure the rate of change for the area. Lets say one second has passed by. Now we have a w=1 and l=16. Area of that is 16. original area is 60 (5*12) so the area changed by 44/1sec. Now lets say half a second. w=3 l=14. The area of that is 42. The difference is now 18/0.5sec = 36/1sec. Now the lengths are changing proportional 1gain:1 loss so you can figure out how the rate is changing. Hint: if in every second you gain the same you lose how much are you changing? Again the diagonals change is not constant. try to measure the change from .5 seconds to 1 second and compare the change in length to the change rate of the area. Well is the length of the diagonals increasing? well yes but how much? next i told you the change in area is lowering.

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alright, thanks so much, figured it out :] i got the area decreasing at 44 cm^2/sec the perimeter is constant and the diagonals i increasing at a rate of 3cm/sec.

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