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anonymous
 5 years ago
EVALUATE THE EXPONENTIAL FUNCTION FOR THREE POSITIVE VALUES OF X,THREE NEGATIVE VALUES OF X,AND AT X=0.SHOW YOUR WORK.USE THE RESULTING ORDERED PAIRS TO PLOT THE GRAPH.STATE THE DOMAIN AND RANGE OF THE FUNCTIONATTACH GRAPH AS LISTED AND REQUIRED.F(X)=E^X1
anonymous
 5 years ago
EVALUATE THE EXPONENTIAL FUNCTION FOR THREE POSITIVE VALUES OF X,THREE NEGATIVE VALUES OF X,AND AT X=0.SHOW YOUR WORK.USE THE RESULTING ORDERED PAIRS TO PLOT THE GRAPH.STATE THE DOMAIN AND RANGE OF THE FUNCTIONATTACH GRAPH AS LISTED AND REQUIRED.F(X)=E^X1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0please help me out in this......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that the question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes this is the question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, substitute and three positive values of x, say 1,2,3 and three negative values, say 1,2,3 in f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for x =1, f(x) = f(1) = (e^1) 1 use your calculator or google to find the value of e^1 and subtract 1 from that to get f(1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just go to google.com and type e^1. you will get a value. try it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0according to google calculator e^1 is 0.367879441. so (e^1) 1 = 0.632120559 so at x = 1, f(x) = 0.632120559

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0similarly find out values of f(x) for x =2,3 and x = 1,2,3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use those values and make a graph such as this: f(x)        >x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0iam new to this..thts why getting problems

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay I understand. But now I have shown you the procedure. Just follow it. Its easy. You can do it. Did you try typing it in google?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i did but i dint got

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay. do you have a scientific calculator with you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you type in e^1 exactly as I typed it? just copy e^1 and paste it in google. and press enter.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay what did you get?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me in another question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got the same which you got

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay good, just do the same for other numbers and you will get your answers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, I can help you. But your new problem separately.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0post your new problem separately.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok can i post it here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no.. post it separately. this post is too long already

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dont see it zehera.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think that i have poted it before thts y it not coming once again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0eveluate the exponentaial eqution forthree positive valu f x,and three negative values of x,and at x=0.transform the second expression into the equivalent logarithm equation and evalaute the logarithm equation for thre values of x that are greater than 1,three values of x that are between 0 and1,and at x=1.show your work.use the resulting ordered pairs to plot the graph of each function.Y=5x^2,X=5y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so Y = 5x^2 is equation 1 and X = 5Y^2 is equation 2 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on google i got this but ith another equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im getting positive values but for negative vl\alues iam getting confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, ;ets make it simpler then. what is x^2 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok it would be greatful

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay. but what is x^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its given that Y=5X^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, tell me what x^2 means. I dont want maths. Just tell me in plain english. What do you think x^2 means?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay. \[x ^{2} = 1/x ^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, \[5x ^{2} = 5/x ^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that means, \[Y = 5/x ^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so now substitute x = 1,2,3 and 1,2,3 and get Y values. what is the value of Y at 0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0any value at log0 is 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are just asked to evaluate the first equation. Why are you taking log?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok you explain me how to do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if we take one value as 2 thn y=5/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok like this we have to take the other two values

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right. But the question also asks for x =0 . so what happens if you take another value as 0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just put 0 in the equation. see what you get. y = 5/0. what is anything divided by 0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we have to take three values as 0,1,2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, anything multiplied by 0 is 0. anything divided by zero is infinity.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, pay attention zehera. the problem asks for three positive values. so you use any three positive values. Similarly use three negative values. then use x = 0 which is neither positive nor negative.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so totally you have 7 values, three positive, three negative and one 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay. now second equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0while taking negative values we get 5/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does the problem say you should do with the second equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if x = 2, what is x ^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 = x * x. so, if x = 2, x * x = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then for x = 2, Y = ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but you just said (2)^2 = 4 so Y = 5/4.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but here the poer is 2 na

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you talking about equation 1 or equation 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay i was talking about equation 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does the problem say to do with equation 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0same as we did in equation 1 but here we have to take negative values

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, pay attention. The problem says transform equation 2 to its logarthmic form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im jst getting confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There are two parts of the problem. We finished the first part using equation 1. Now the second part of the problem says transform the second equation to logarithm form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the second equation is X=5y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you transform it to logarithms by taking log on both sides. that is log X = log(5y^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is all I can explain. You should be able to take it from there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are welcome. try to understand what you are doing and you will get your answers easily. good luck!
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