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anonymous

  • 5 years ago

What is the square root of 90 times the square root of 40?

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  1. anonymous
    • 5 years ago
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    √(90)(√(40))=60

  2. anonymous
    • 5 years ago
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    How would you factor that problem out?

  3. anonymous
    • 5 years ago
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    I have answered your previous post with solution

  4. anonymous
    • 5 years ago
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    \[\sqrt{90}*\sqrt{40} = \sqrt{90*40} = \sqrt{3600} = \sqrt{36 * 100} \]\[= \sqrt{36} * \sqrt{100} = 6 * 10\]

  5. anonymous
    • 5 years ago
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    \[\sqrt{90}\times \sqrt{40}\]

  6. anonymous
    • 5 years ago
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    polpak plz ....if u can help me.......c ma quesn

  7. anonymous
    • 5 years ago
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    How would you do this problem: square root of 3x times the square root of 8x to third power?

  8. anonymous
    • 5 years ago
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    The same way. Multiply the stuff under the radical, then pull out squares.

  9. anonymous
    • 5 years ago
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    Start by multiplying the things under the radical, what do you get? \[\sqrt{3x}*\sqrt{8x^3} = \sqrt{???}\]

  10. anonymous
    • 5 years ago
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    24xto the 4th

  11. anonymous
    • 5 years ago
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    Right. So \(x^4 = (?)^2\)

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