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The base of an isosceles triangle is 20 cm. and the altitude is increasing at a rate of 1 cm./min. At what rate is the base angle increasing when the area of the triangle is 100 cm^2?
 3 years ago
 3 years ago
The base of an isosceles triangle is 20 cm. and the altitude is increasing at a rate of 1 cm./min. At what rate is the base angle increasing when the area of the triangle is 100 cm^2?
 3 years ago
 3 years ago

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JSBest ResponseYou've already chosen the best response.0
im confused as to what your asking...can you clarify so I can help you out?
 3 years ago

a933793Best ResponseYou've already chosen the best response.0
http://adf.ly/1EjFf ^ Diagram. If we were to look at the middle line, h. We can set up a trigonometric function to describe the relation of the increasing altitude and the angle, correct?
 3 years ago

a933793Best ResponseYou've already chosen the best response.0
We can say: tan(x)=h/(a/2)=2h/a but! we know that two of those values are changing with respect to time dh/dt=1cm/min So we can get: tan(dx/dt)=(2dh/dt)/a Also note that we an figure out the a/2 or a term by recalling the area of a triangle.
 3 years ago

sharrymathBest ResponseYou've already chosen the best response.0
I am unable to see your diagram.
 3 years ago
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