anonymous
  • anonymous
How do you figure out this for factor by grouping 6x^3-6x^2-x+1
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
(x-1) (6x^2 -1)
anonymous
  • anonymous
if u like the answer ...pls fan me ..thanx
anonymous
  • anonymous
then I have another one to see if it is correct I have 6^6-64

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anonymous
  • anonymous
my answer (b+2)(b^2-2b+4)(b-2)(b^2-2b+4)
anonymous
  • anonymous
r u typing?
anonymous
  • anonymous
hello, r u there?
anonymous
  • anonymous
yes I am here
anonymous
  • anonymous
Small ever in that factorisation: one of the (-2b) should be +2b
anonymous
  • anonymous
i m waiting for the question
anonymous
  • anonymous
error* eugh
anonymous
  • anonymous
b^6-64
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
OK, Ignore me then... ¬_¬
anonymous
  • anonymous
its (b-8)(b+8)
anonymous
  • anonymous
because of (a^2 - b^2) =( a-b) (a+b)
anonymous
  • anonymous
it should (b+2)(b^2-2b+4)(b-2)(b^2+2b+4)
anonymous
  • anonymous
hey !!! was that squared or raised to power of 6 ? 6???
anonymous
  • anonymous
Yes, that is right.
anonymous
  • anonymous
ok i misread it
anonymous
  • anonymous
sry
anonymous
  • anonymous
no problem
anonymous
  • anonymous
thank you INewton
anonymous
  • anonymous
No problem.
anonymous
  • anonymous
tht math looks confusing but im just watching cuz im going 2 hav 2 do this sometime in life
anonymous
  • anonymous
u will be fine macy....its not really hard...
anonymous
  • anonymous
ok thanks ;)
anonymous
  • anonymous
i cant type in group chat :(
anonymous
  • anonymous
oh y?
anonymous
  • anonymous
Reload the website.
anonymous
  • anonymous
smtimes ...it just doesnt work...
anonymous
  • anonymous
ohhhh. or u can refresh it wen tht hapens i refresh and it works
anonymous
  • anonymous
didnt work for me.....:((
anonymous
  • anonymous
oh
anonymous
  • anonymous
macy r u on gmail or yahoo?
anonymous
  • anonymous
im nt aloud 2 give my email on here either
anonymous
  • anonymous
ok because its not really good to talk in someone's question...thats all..
anonymous
  • anonymous
hmmmmm im thinken and thinken and drawing a blank
anonymous
  • anonymous
wait IDEA!!!!
anonymous
  • anonymous
hahah
anonymous
  • anonymous
wat?
anonymous
  • anonymous
either me or u can make a question like hey or something and talk on tht
anonymous
  • anonymous
i feel smart
anonymous
  • anonymous
hahah......u r really smart
anonymous
  • anonymous
awww thanks
anonymous
  • anonymous
go 2 the next question thts posted ok?
anonymous
  • anonymous
u there?
anonymous
  • anonymous
I have a question polynomial 0.041h-0.018a-2.69 can be used to estimate the lung capacity, in liters of a female with height h, in centimeters, and age a, in years. Find the lung capacity of a 30 year old woman who is 170 centimeters tall. Her lung capacity is approximately_____ liters?
anonymous
  • anonymous
I am confused on how you go about figuring out this problem
anonymous
  • anonymous
Lung Capacity (h, a) = 0.041h-0.018a-2.69 Let h = 170 , a = 30 => Lung Capacity (170, 30) = 0.041 x 170 - 0.018 x 30 - 2.69
anonymous
  • anonymous
the answer would be 206 liters
anonymous
  • anonymous
0.041 x 170 - 0.018 x 30 - 2.69 = 3.74...
anonymous
  • anonymous
ok i see what i did wrong
anonymous
  • anonymous
Was your mistake considering the possibility that my advice was incorrect?
anonymous
  • anonymous
what i did was took 0.041* 170=6.97-.018=6.952*30=208.56-2.69=205.87
anonymous
  • anonymous
Ah, I see; glad you sorted it.
anonymous
  • anonymous
but if you do the mutliplication first 0.041*170=6.97 & .018*30=.54 then you subtract 6.97-.54-2.69=3.74

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