How do you figure out this for factor by grouping 6x^3-6x^2-x+1

- anonymous

How do you figure out this for factor by grouping 6x^3-6x^2-x+1

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

(x-1) (6x^2 -1)

- anonymous

if u like the answer ...pls fan me ..thanx

- anonymous

then I have another one to see if it is correct I have 6^6-64

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

my answer (b+2)(b^2-2b+4)(b-2)(b^2-2b+4)

- anonymous

r u typing?

- anonymous

hello, r u there?

- anonymous

yes I am here

- anonymous

Small ever in that factorisation: one of the (-2b) should be +2b

- anonymous

i m waiting for the question

- anonymous

error* eugh

- anonymous

b^6-64

- anonymous

oh ok

- anonymous

OK, Ignore me then... ¬_¬

- anonymous

its (b-8)(b+8)

- anonymous

because of (a^2 - b^2) =( a-b) (a+b)

- anonymous

it should (b+2)(b^2-2b+4)(b-2)(b^2+2b+4)

- anonymous

hey !!! was that squared or raised to power of 6 ? 6???

- anonymous

Yes, that is right.

- anonymous

ok i misread it

- anonymous

sry

- anonymous

no problem

- anonymous

thank you INewton

- anonymous

No problem.

- anonymous

tht math looks confusing but im just watching cuz im going 2 hav 2 do this sometime in life

- anonymous

u will be fine macy....its not really hard...

- anonymous

ok thanks ;)

- anonymous

i cant type in group chat :(

- anonymous

oh y?

- anonymous

Reload the website.

- anonymous

smtimes ...it just doesnt work...

- anonymous

ohhhh. or u can refresh it wen tht hapens i refresh and it works

- anonymous

didnt work for me.....:((

- anonymous

oh

- anonymous

macy r u on gmail or yahoo?

- anonymous

im nt aloud 2 give my email on here either

- anonymous

ok because its not really good to talk in someone's question...thats all..

- anonymous

hmmmmm im thinken and thinken and drawing a blank

- anonymous

wait IDEA!!!!

- anonymous

hahah

- anonymous

wat?

- anonymous

either me or u can make a question like hey or something and talk on tht

- anonymous

i feel smart

- anonymous

hahah......u r really smart

- anonymous

awww thanks

- anonymous

go 2 the next question thts posted ok?

- anonymous

u there?

- anonymous

I have a question polynomial 0.041h-0.018a-2.69 can be used to estimate the lung capacity, in liters of a female with height h, in centimeters, and age a, in years. Find the lung capacity of a 30 year old woman who is 170 centimeters tall. Her lung capacity is approximately_____ liters?

- anonymous

I am confused on how you go about figuring out this problem

- anonymous

Lung Capacity (h, a) = 0.041h-0.018a-2.69
Let h = 170 , a = 30
=> Lung Capacity (170, 30) = 0.041 x 170 - 0.018 x 30 - 2.69

- anonymous

the answer would be 206 liters

- anonymous

0.041 x 170 - 0.018 x 30 - 2.69 = 3.74...

- anonymous

ok i see what i did wrong

- anonymous

Was your mistake considering the possibility that my advice was incorrect?

- anonymous

what i did was took 0.041* 170=6.97-.018=6.952*30=208.56-2.69=205.87

- anonymous

Ah, I see; glad you sorted it.

- anonymous

but if you do the mutliplication first 0.041*170=6.97 & .018*30=.54 then you subtract 6.97-.54-2.69=3.74

Looking for something else?

Not the answer you are looking for? Search for more explanations.