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(x-1) (6x^2 -1)
if u like the answer ...pls fan me ..thanx
then I have another one to see if it is correct I have 6^6-64
my answer (b+2)(b^2-2b+4)(b-2)(b^2-2b+4)
r u typing?
hello, r u there?
yes I am here
Small ever in that factorisation: one of the (-2b) should be +2b
i m waiting for the question
OK, Ignore me then... ¬_¬
because of (a^2 - b^2) =( a-b) (a+b)
it should (b+2)(b^2-2b+4)(b-2)(b^2+2b+4)
hey !!! was that squared or raised to power of 6 ? 6???
Yes, that is right.
ok i misread it
thank you INewton
tht math looks confusing but im just watching cuz im going 2 hav 2 do this sometime in life
u will be fine macy....its not really hard...
ok thanks ;)
i cant type in group chat :(
Reload the website.
smtimes ...it just doesnt work...
ohhhh. or u can refresh it wen tht hapens i refresh and it works
didnt work for me.....:((
macy r u on gmail or yahoo?
im nt aloud 2 give my email on here either
ok because its not really good to talk in someone's question...thats all..
hmmmmm im thinken and thinken and drawing a blank
either me or u can make a question like hey or something and talk on tht
i feel smart
hahah......u r really smart
go 2 the next question thts posted ok?
I have a question polynomial 0.041h-0.018a-2.69 can be used to estimate the lung capacity, in liters of a female with height h, in centimeters, and age a, in years. Find the lung capacity of a 30 year old woman who is 170 centimeters tall. Her lung capacity is approximately_____ liters?
I am confused on how you go about figuring out this problem
Lung Capacity (h, a) = 0.041h-0.018a-2.69 Let h = 170 , a = 30 => Lung Capacity (170, 30) = 0.041 x 170 - 0.018 x 30 - 2.69
the answer would be 206 liters
0.041 x 170 - 0.018 x 30 - 2.69 = 3.74...
ok i see what i did wrong
Was your mistake considering the possibility that my advice was incorrect?
what i did was took 0.041* 170=6.97-.018=6.952*30=208.56-2.69=205.87
Ah, I see; glad you sorted it.
but if you do the mutliplication first 0.041*170=6.97 & .018*30=.54 then you subtract 6.97-.54-2.69=3.74