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Ewwww geometry. That is all.
cant apply anythng here.........
The Euler Line of the triangle starts at the circumcenter, goes through the centroid, to the orthocenter... It's a start.
Lol at that being a start..
wtf........jas cant read ur minds
It's apparently a purely geometric proof. http://planetmath.org/encyclopedia/EulerLineProof.html
You thought it was going to be something other than geometric...?
I was hopeful...
If I had formulas for centroid, orthocenter, and circumcenter of a scalene triangle based upon the vertexes, I could in theory show the ratio of the distances is always 1/2.
No, you couldn't. Regardless of whether it is possible, YOU couldn't do it.
I didn't see the need to be degrading. I am simply here to try to help.
Just joshin', no need to call a wambulance :(
this is what I have so far, since there is no restrictions to define a scalene other than different angles/side lenths...a right scalene should prove it just as well.... i used the 3-4-5
if I could prove that the line bisects the hypot at a right angle, its solved lol
Unfortunately, I think proof need to be more general than 'it works for a RA with these sides => it works for all' But I hate geometry, so meh.
feeling sleepy....c u guys later
thats true, proofs need to be more rigorous, but I aint to good with that part ;)
I am. When there's no drawing involved.
I get congruent triangles like this..... but is there a theorum which states that the apex of a triangle within an rectangle has a ratio of sides equal to the distance between the 2 top corners?
Since we have 2 congruent triangles with equal angles A and B, then the ration of 50/3 sinB would match 25/3 sinB to be true.