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anonymous

  • 5 years ago

prove that the centroid of a scalene triangle divides the line joining orthocenter and circumcenter in the ratio 2:1

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  1. anonymous
    • 5 years ago
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    Ewwww geometry. That is all.

  2. anonymous
    • 5 years ago
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    cant apply anythng here.........

  3. anonymous
    • 5 years ago
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    The Euler Line of the triangle starts at the circumcenter, goes through the centroid, to the orthocenter... It's a start.

  4. anonymous
    • 5 years ago
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    Lol at that being a start..

  5. anonymous
    • 5 years ago
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    wtf........jas cant read ur minds

  6. anonymous
    • 5 years ago
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    It's apparently a purely geometric proof. http://planetmath.org/encyclopedia/EulerLineProof.html

  7. anonymous
    • 5 years ago
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    You thought it was going to be something other than geometric...?

  8. anonymous
    • 5 years ago
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    I was hopeful...

  9. anonymous
    • 5 years ago
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  10. anonymous
    • 5 years ago
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    If I had formulas for centroid, orthocenter, and circumcenter of a scalene triangle based upon the vertexes, I could in theory show the ratio of the distances is always 1/2.

  11. anonymous
    • 5 years ago
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    No, you couldn't. Regardless of whether it is possible, YOU couldn't do it.

  12. anonymous
    • 5 years ago
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    Ouch...

  13. anonymous
    • 5 years ago
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    You're welcome.

  14. anonymous
    • 5 years ago
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    I didn't see the need to be degrading. I am simply here to try to help.

  15. anonymous
    • 5 years ago
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    Just joshin', no need to call a wambulance :(

  16. amistre64
    • 5 years ago
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    this is what I have so far, since there is no restrictions to define a scalene other than different angles/side lenths...a right scalene should prove it just as well.... i used the 3-4-5

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  17. amistre64
    • 5 years ago
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    if I could prove that the line bisects the hypot at a right angle, its solved lol

  18. anonymous
    • 5 years ago
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    Unfortunately, I think proof need to be more general than 'it works for a RA with these sides => it works for all' But I hate geometry, so meh.

  19. anonymous
    • 5 years ago
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    feeling sleepy....c u guys later

  20. amistre64
    • 5 years ago
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    thats true, proofs need to be more rigorous, but I aint to good with that part ;)

  21. anonymous
    • 5 years ago
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    I am. When there's no drawing involved.

  22. amistre64
    • 5 years ago
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    I get congruent triangles like this..... but is there a theorum which states that the apex of a triangle within an rectangle has a ratio of sides equal to the distance between the 2 top corners?

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  23. amistre64
    • 5 years ago
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    Since we have 2 congruent triangles with equal angles A and B, then the ration of 50/3 sinB would match 25/3 sinB to be true.

  24. amistre64
    • 5 years ago
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    got it!!

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