anonymous
  • anonymous
What would be the most logical first step to solve this quadratic equation? x2+2x+13=8
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
what level is this? (that equation only has imaginary roots and, without stereotyping, most people who know about imaginary numbers can solve quadratics)
anonymous
  • anonymous
just use ur quadtratic equatin and substitute.
anonymous
  • anonymous
so would it be the square root of both sides .

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anonymous
  • anonymous
is it x^2?
anonymous
  • anonymous
Did you make up this question yourself?
anonymous
  • anonymous
no its algebra twilight math class .
anonymous
  • anonymous
its not complicated, just put in the quadtratic formula, the values of Ax +Bx +C=0, where in ur case, its x^2 +2x +5 =0..... or am i missing something...
anonymous
  • anonymous
Hmm. Well the first step would be to either set it to 0, or complete the square. It won't factorise, so I'd complete the square. But you'll still need to square root a negative number.
anonymous
  • anonymous
i dont know how to do that sorry im not qood at math worse subject evr .
anonymous
  • anonymous
Note \[\sqrt{-1} = i \]
anonymous
  • anonymous
where do u see a negative value?
anonymous
  • anonymous
nvm is see it now...
anonymous
  • anonymous
{ -2 ± Sq Root ( 4 - 20 ) } / 2
anonymous
  • anonymous
unless u use imaginary numbers, thats as simplified as it gets...
amistre64
  • amistre64
subtract the right hand side from both sides of the equation would be the first step
amistre64
  • amistre64
x2+2x+13 -8=8 -8 x^2 +2x +5 = 0
amistre64
  • amistre64
the next step would be to "complete the square".... if you dont know the quadratic formula that is :) x^2 +2x +5 = 0 ; subtract 5 from both sides x^2 +2x + ___ = -5 + ____ we need to find a suitable number to fill in these blanks with; we need to create a "perfect" square trinomial that will factor into: (x+?)^2 we know that the product of a binomial and itself is: (a+b)(a+b) = a^2 +2ab + b^2 what we have is: a^2 +a(2__ ) + (___)^2
anonymous
  • anonymous
I know the quadratic formula, but would still complete the square.
amistre64
  • amistre64
if I recall correctly, completing the sqaure is how we get the quadratic formula :)
anonymous
  • anonymous
Affirmative.
anonymous
  • anonymous
lol.
anonymous
  • anonymous
man im in university calc, and i dont even remember how to complete the square...havent done that since 9th grade haha
amistre64
  • amistre64
(a+b)(a+b) = a^2 +2ab + b^2 what we have is: a^2 +a(2__ ) + (___)^2 we see that if we divide the midde term by 2a we will get a suitable "b" right? x^2 +2x +5 ....2x/2x = 1...b=1 b^2 = 1
anonymous
  • anonymous
pellet, university calc. That's harcore.
anonymous
  • anonymous
hardcore* :@
amistre64
  • amistre64
x^2 +2x +1 = -5+1 (x+1)^2 = -4 already see a problem lol x+1 = +-sqrt(-4) x = -1 +- sqrt(-4)
anonymous
  • anonymous
its also really hard, and i dont know why i need it if im in software engineering, but ok...
anonymous
  • anonymous
Because Maths is everything.
amistre64
  • amistre64
x = -1 +- 2i :) but thats a complex number and not a "real" number
anonymous
  • anonymous
\[x^2 + 2x + 13 = 8 \] \[\iff (x+1)^2 = -4 \] \[\implies (x+1) = \pm \sqrt{-4} = \pm \sqrt{-1}\sqrt{4} = \pm 2i \] \[\implies x = -1 \pm 2i \]
anonymous
  • anonymous
sorry had that typed out but realised you were explaining it so waited - but didn;t want all that typing to go to waste.
amistre64
  • amistre64
lol ..... you did good ;)
amistre64
  • amistre64
does that make any sense miranda?
anonymous
  • anonymous
... :(
anonymous
  • anonymous
im sure thats a yes ;)

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