A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
What would be the most logical first step to solve this quadratic equation?
x2+2x+13=8
anonymous
 5 years ago
What would be the most logical first step to solve this quadratic equation? x2+2x+13=8

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what level is this? (that equation only has imaginary roots and, without stereotyping, most people who know about imaginary numbers can solve quadratics)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just use ur quadtratic equatin and substitute.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so would it be the square root of both sides .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Did you make up this question yourself?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no its algebra twilight math class .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its not complicated, just put in the quadtratic formula, the values of Ax +Bx +C=0, where in ur case, its x^2 +2x +5 =0..... or am i missing something...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hmm. Well the first step would be to either set it to 0, or complete the square. It won't factorise, so I'd complete the square. But you'll still need to square root a negative number.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know how to do that sorry im not qood at math worse subject evr .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Note \[\sqrt{1} = i \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where do u see a negative value?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0{ 2 ± Sq Root ( 4  20 ) } / 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0unless u use imaginary numbers, thats as simplified as it gets...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0subtract the right hand side from both sides of the equation would be the first step

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x2+2x+13 8=8 8 x^2 +2x +5 = 0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the next step would be to "complete the square".... if you dont know the quadratic formula that is :) x^2 +2x +5 = 0 ; subtract 5 from both sides x^2 +2x + ___ = 5 + ____ we need to find a suitable number to fill in these blanks with; we need to create a "perfect" square trinomial that will factor into: (x+?)^2 we know that the product of a binomial and itself is: (a+b)(a+b) = a^2 +2ab + b^2 what we have is: a^2 +a(2__ ) + (___)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know the quadratic formula, but would still complete the square.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if I recall correctly, completing the sqaure is how we get the quadratic formula :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0man im in university calc, and i dont even remember how to complete the square...havent done that since 9th grade haha

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(a+b)(a+b) = a^2 +2ab + b^2 what we have is: a^2 +a(2__ ) + (___)^2 we see that if we divide the midde term by 2a we will get a suitable "b" right? x^2 +2x +5 ....2x/2x = 1...b=1 b^2 = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pellet, university calc. That's harcore.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 +2x +1 = 5+1 (x+1)^2 = 4 already see a problem lol x+1 = +sqrt(4) x = 1 + sqrt(4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its also really hard, and i dont know why i need it if im in software engineering, but ok...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Because Maths is everything.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x = 1 + 2i :) but thats a complex number and not a "real" number

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^2 + 2x + 13 = 8 \] \[\iff (x+1)^2 = 4 \] \[\implies (x+1) = \pm \sqrt{4} = \pm \sqrt{1}\sqrt{4} = \pm 2i \] \[\implies x = 1 \pm 2i \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry had that typed out but realised you were explaining it so waited  but didn;t want all that typing to go to waste.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol ..... you did good ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0does that make any sense miranda?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im sure thats a yes ;)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.