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anonymous

  • 5 years ago

Multiply: 1.) [sqrt.2x^2] * [10x^6] 2.) [2x sqrt.12x] * [3 sqrt.4x] 3.) 6 sqrt.5 ( [srt.11] + [sqrt.5] )

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  1. anonymous
    • 5 years ago
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    please help

  2. anonymous
    • 5 years ago
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    It's impossible to solve it. You need to make it more clear. Try using the equation button or taking a picture of the questions and attaching it here.

  3. anonymous
    • 5 years ago
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    ^ = to the power sqrt. = that square root sign

  4. anonymous
    • 5 years ago
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    oh nevermind i just saw the eqaution button , holdon

  5. anonymous
    • 5 years ago
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    Yeah, but would it be \[\sqrt{(2x)^{2}} * (10x)^{^{6}}\] or \[(\sqrt{2x})^{^{2}}*10x ^{6}\] ?

  6. anonymous
    • 5 years ago
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    \[1.) \sqrt{2x ^{2}} \times \sqrt{10x ^{6}}\]

  7. anonymous
    • 5 years ago
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    2.) \[(2x \sqrt{12x} ) (3\sqrt{4x})\]

  8. anonymous
    • 5 years ago
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    3.) \[6\sqrt{5} (5\sqrt{11} + \sqrt{5})\]

  9. anonymous
    • 5 years ago
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    \[\sqrt{2} x * \sqrt{10} x ^{3}\] \[2 \sqrt{5} x ^{4}\]

  10. anonymous
    • 5 years ago
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    ok now?

  11. anonymous
    • 5 years ago
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    why wouldn't it be \[2x ^{2}\sqrt{5}\]

  12. anonymous
    • 5 years ago
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    nevermind, I thought the x^4 was in the sqrt.

  13. anonymous
    • 5 years ago
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    well khmath i think your right

  14. anonymous
    • 5 years ago
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    oh never mind neither answers show here

  15. anonymous
    • 5 years ago
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    would it be \[2x ^{4} \sqrt{5}\]

  16. anonymous
    • 5 years ago
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    ?

  17. anonymous
    • 5 years ago
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    yes..

  18. anonymous
    • 5 years ago
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    and for the rest of the problems ?

  19. anonymous
    • 5 years ago
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    u figured out the second one ...right??/

  20. anonymous
    • 5 years ago
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    it wasnt right

  21. anonymous
    • 5 years ago
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    i just was asking if it was

  22. anonymous
    • 5 years ago
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    ok lets do it again...

  23. anonymous
    • 5 years ago
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    are you sure you know how to do this ?

  24. anonymous
    • 5 years ago
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    yes i do

  25. anonymous
    • 5 years ago
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    ok just making sure

  26. anonymous
    • 5 years ago
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    4sqrt(3) x * sqrt(x) * 6 * sqrt(x) 24 sqrt(3) *x

  27. anonymous
    • 5 years ago
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    mm.. 24 sqrt(3) *x * sqrt(x)

  28. anonymous
    • 5 years ago
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    for the second ?

  29. anonymous
    • 5 years ago
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    ya

  30. anonymous
    • 5 years ago
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    no it doesnt give that answer here as an option :/

  31. anonymous
    • 5 years ago
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    wait i dont get which one you wrote

  32. anonymous
    • 5 years ago
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    the second one

  33. anonymous
    • 5 years ago
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    but which was your answer

  34. anonymous
    • 5 years ago
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    let me rewrite again

  35. anonymous
    • 5 years ago
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    one min

  36. anonymous
    • 5 years ago
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    24 sqrt3 x^2

  37. anonymous
    • 5 years ago
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    final answer...

  38. anonymous
    • 5 years ago
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    now first two are solved...okay?

  39. anonymous
    • 5 years ago
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    \[24\sqrt{3x ^{2}}\]

  40. anonymous
    • 5 years ago
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    ?

  41. anonymous
    • 5 years ago
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    no ...x^2 is not under the square root

  42. anonymous
    • 5 years ago
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    so just 3x alone ?

  43. anonymous
    • 5 years ago
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    wait a sec

  44. anonymous
    • 5 years ago
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    hmmmm

  45. anonymous
    • 5 years ago
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    \[24 \sqrt{3} \]\[x ^{2}\]

  46. anonymous
    • 5 years ago
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    they r together

  47. anonymous
    • 5 years ago
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    x goes before where ?

  48. anonymous
    • 5 years ago
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    doesnt matter where u write x ,

  49. anonymous
    • 5 years ago
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    thanks , but nevermind i really dont think you know how to this . to many attempts , but thanks for trying to help

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spraguer (Moderator)
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