anonymous
  • anonymous
Multiply: 1.) [sqrt.2x^2] * [10x^6] 2.) [2x sqrt.12x] * [3 sqrt.4x] 3.) 6 sqrt.5 ( [srt.11] + [sqrt.5] )
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
please help
anonymous
  • anonymous
It's impossible to solve it. You need to make it more clear. Try using the equation button or taking a picture of the questions and attaching it here.
anonymous
  • anonymous
^ = to the power sqrt. = that square root sign

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anonymous
  • anonymous
oh nevermind i just saw the eqaution button , holdon
anonymous
  • anonymous
Yeah, but would it be \[\sqrt{(2x)^{2}} * (10x)^{^{6}}\] or \[(\sqrt{2x})^{^{2}}*10x ^{6}\] ?
anonymous
  • anonymous
\[1.) \sqrt{2x ^{2}} \times \sqrt{10x ^{6}}\]
anonymous
  • anonymous
2.) \[(2x \sqrt{12x} ) (3\sqrt{4x})\]
anonymous
  • anonymous
3.) \[6\sqrt{5} (5\sqrt{11} + \sqrt{5})\]
anonymous
  • anonymous
\[\sqrt{2} x * \sqrt{10} x ^{3}\] \[2 \sqrt{5} x ^{4}\]
anonymous
  • anonymous
ok now?
anonymous
  • anonymous
why wouldn't it be \[2x ^{2}\sqrt{5}\]
anonymous
  • anonymous
nevermind, I thought the x^4 was in the sqrt.
anonymous
  • anonymous
well khmath i think your right
anonymous
  • anonymous
oh never mind neither answers show here
anonymous
  • anonymous
would it be \[2x ^{4} \sqrt{5}\]
anonymous
  • anonymous
?
anonymous
  • anonymous
yes..
anonymous
  • anonymous
and for the rest of the problems ?
anonymous
  • anonymous
u figured out the second one ...right??/
anonymous
  • anonymous
it wasnt right
anonymous
  • anonymous
i just was asking if it was
anonymous
  • anonymous
ok lets do it again...
anonymous
  • anonymous
are you sure you know how to do this ?
anonymous
  • anonymous
yes i do
anonymous
  • anonymous
ok just making sure
anonymous
  • anonymous
4sqrt(3) x * sqrt(x) * 6 * sqrt(x) 24 sqrt(3) *x
anonymous
  • anonymous
mm.. 24 sqrt(3) *x * sqrt(x)
anonymous
  • anonymous
for the second ?
anonymous
  • anonymous
ya
anonymous
  • anonymous
no it doesnt give that answer here as an option :/
anonymous
  • anonymous
wait i dont get which one you wrote
anonymous
  • anonymous
the second one
anonymous
  • anonymous
but which was your answer
anonymous
  • anonymous
let me rewrite again
anonymous
  • anonymous
one min
anonymous
  • anonymous
24 sqrt3 x^2
anonymous
  • anonymous
final answer...
anonymous
  • anonymous
now first two are solved...okay?
anonymous
  • anonymous
\[24\sqrt{3x ^{2}}\]
anonymous
  • anonymous
?
anonymous
  • anonymous
no ...x^2 is not under the square root
anonymous
  • anonymous
so just 3x alone ?
anonymous
  • anonymous
wait a sec
anonymous
  • anonymous
hmmmm
anonymous
  • anonymous
\[24 \sqrt{3} \]\[x ^{2}\]
anonymous
  • anonymous
they r together
anonymous
  • anonymous
x goes before where ?
anonymous
  • anonymous
doesnt matter where u write x ,
anonymous
  • anonymous
thanks , but nevermind i really dont think you know how to this . to many attempts , but thanks for trying to help

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