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anonymous

  • 5 years ago

PLEASSSEEEE help 1/2log(low8)x=3log(low8)3

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  1. anonymous
    • 5 years ago
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    kk hold on a second,

  2. anonymous
    • 5 years ago
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    so ur trying to solve for x?

  3. anonymous
    • 5 years ago
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    yes!!!!

  4. anonymous
    • 5 years ago
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    mk, the answer is pretty simple(if im doing this correctly) give me a min to write it out in equation form

  5. anonymous
    • 5 years ago
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    \[1/2 \log_{8} x = 3\log_{8} 3\] whic\[x = \sqrt{9}\]h becomes \[\log_{8} \sqrt{x} = \log_{8} 3^{3}\] since any value to the exponent 1/2 is a square root. now drop the log 8 and it gives you \[\sqrt{x} = 9\] where \[x = \sqrt{9}\] therefore, x = 3

  6. anonymous
    • 5 years ago
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    wow my whole message got fluttered up. hold on

  7. anonymous
    • 5 years ago
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    k well im not gonna rewrite it ignore the square root 9 at the top. what u need ot grasp is by following logarithm rules, you know that the values in front of the logaritms become exponent of values after log. therefore x ^ 1/2 is simply square root of x and on the other side 3^3 is 9. actually i think i made a mistake, when u get rid of the sqrt root u square both sides, so x is actually equal to 9^2, which is 81.

  8. anonymous
    • 5 years ago
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    hope it helps.

  9. anonymous
    • 5 years ago
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    the answer was 729 ?! oh well i alreaody its already graded now! thanks for your help tho!

  10. anonymous
    • 5 years ago
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    oh pellet... flutter dude 3^3 is 27 MY BAD! so 27 ^2 is 729!!!

  11. anonymous
    • 5 years ago
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    so it was the right way to do it i just did 3^3 wrong :(...im sorry!

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