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- anonymous

PLEASSSEEEE help
1/2log(low8)x=3log(low8)3

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- anonymous

PLEASSSEEEE help
1/2log(low8)x=3log(low8)3

- katieb

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- anonymous

kk hold on a second,

- anonymous

so ur trying to solve for x?

- anonymous

yes!!!!

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- anonymous

mk, the answer is pretty simple(if im doing this correctly)
give me a min to write it out in equation form

- anonymous

\[1/2 \log_{8} x = 3\log_{8} 3\]
whic\[x = \sqrt{9}\]h becomes
\[\log_{8} \sqrt{x} = \log_{8} 3^{3}\]
since any value to the exponent 1/2 is a square root.
now drop the log 8 and it gives you
\[\sqrt{x} = 9\]
where
\[x = \sqrt{9}\]
therefore, x = 3

- anonymous

wow my whole message got fluttered up. hold on

- anonymous

k well im not gonna rewrite it ignore the square root 9 at the top.
what u need ot grasp is by following logarithm rules, you know that the values in front of the logaritms become exponent of values after log. therefore x ^ 1/2 is simply square root of x and on the other side 3^3 is 9.
actually i think i made a mistake, when u get rid of the sqrt root u square both sides, so x is actually equal to 9^2, which is 81.

- anonymous

hope it helps.

- anonymous

the answer was 729 ?! oh well i alreaody its already graded now! thanks for your help tho!

- anonymous

oh pellet...
flutter
dude 3^3 is 27 MY BAD!
so 27 ^2 is 729!!!

- anonymous

so it was the right way to do it i just did 3^3 wrong :(...im sorry!

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