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Define 'factoring' - because that isn't something I'd look to factorise.

u cant solve for b and h in same equation

Define b = h+7 (or h = b-7) , and go from there.

The last one =22 too :@

Post the quadratic equation you get when you follow through with INewton's suggestion.

My suggestion is to use the first one:\[(1/2) \times h \times(h + 7)=22 cm sq\]

1/2*h(h+7)=22
1/2(h^2+h7)=22
2*1/2(h^2+h7)=2*22
h^2+h7=44
h^2-h7=44=44-44
h^2+h7-44=0
h=9 b=35

\[h ^{2}+7h-44=0\] I meant to type sri

which method did you use to get 9 for h??

i think factor

yes please

It will start looking like this:
(h- ?) (h +?)
the ?*?=-44
and ?+?=-7

Any questions??? so far.

11 & 4

Right on!!
(h+11)(h-4)=0

which one do you think is the answer? the -11 or the 4 ???

very good, now remember the base was equal to the height + 7 cm, so what is the base?

11

Correcto, you seem to have a handle on this problem, good luck.

thank you very much

No problem, and INewton's input was helpful.