solve for x and y by substitution: x/3+y/4=2 2x/3-y/2=0

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solve for x and y by substitution: x/3+y/4=2 2x/3-y/2=0

Mathematics
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SOMEONE PLEASE HELP ! =(
working on it
thanks!

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Other answers:

simplify the first one then the second
the first one comes out to be 4x-3y=24
the second comes out to be 4x-3y=0
where on earth do you find the 24 from? :S
it becomes 4x/12 + 3y/12 = 2
its the lcm of 3 and 4 and then multiplied by 2 on right hand side
then simplifies to 4x+3y=24
4x-3y=2 -4x-3y=0
same thing as 4x-3y=24 -4x+3y=0

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