## anonymous 5 years ago 1.) 6 sqrt.5 ( [srt.11] + [sqrt.5] ) 2.) (3 sqrt.3 +3 )(6 sqrt. 3 + 2)

1. anonymous

1.) $6\sqrt{5} ( \sqrt{11} + \sqrt{5})$

2. amistre64

what do you come up with when you distribute it thru?

3. anonymous

2.) $(3\sqrt{3} + 3) (6\sqrt{3} + 2)$

4. anonymous

what do you mean ?

5. amistre64

I mean that you need to know what the distributive property is so you can solve these for yourself ;)

6. amistre64

if you want to learn, I can teach you :)

7. amistre64

and posting 2 questions at a time tends to mean you just want someone else to do your homework for you.....

8. anonymous

$2.) 6 + 18\sqrt{3}^{2} + 6\sqrt{3}$

9. anonymous

10. anonymous

and no its not homework its an exam for my course

11. amistre64

its a good start.... but lets check it out...

12. anonymous

i dont think i can simplify it more ?

13. amistre64

(3 sqrt.3 +3 )(6 sqrt. 3 + 2) 3sqrt(3) (6sqrt(3)) = 18(3) 3(2)sqrt(3) = 6sqrt(3) 3(6sqrt(3)) = 18sqrt(3) 3(2)=6

14. anonymous

so im right ? :)

15. amistre64

54+6 +24sqrt(3) 60 + 24sqrt(3) if I did it right :)

16. amistre64

you had 3 terms good, but were missing that forth

17. amistre64

12(5 + 2sqrt(3)) is another way to write it

18. anonymous

ohhh true ! and for the 1st problem i got $6\sqrt{11} + 5$

19. anonymous

im not sure if its right ?

20. amistre64

I got: 6sqrt(55) + 30

21. amistre64

$6\sqrt{5*11} + 6\sqrt{5*5}$

22. anonymous

ahhh true , i thought i was just suppose to cancel it out

23. amistre64

$6\sqrt{55} + 6(5) = 6\sqrt{55}+30$

24. anonymous

$(2x \sqrt{12x}) (3\sqrt{4x})$

25. anonymous

can you help me with that problem aswell ?

26. anonymous

i got $24x ^{2}\sqrt{3}$

27. amistre64

multiplication doesnt care in what order you do it...$2x(3) *\sqrt{12x}*\sqrt{4x} = 6x \sqrt{48x^2}$

28. anonymous

cant i simplify that further ?

29. amistre64

6x 4x sqrt(3) 24x^2 sqrt(3)

30. anonymous

31. amistre64

you were right :)

32. anonymous

thank youuu :) i had to double check ! :D how about this one : $\sqrt{2x ^{2}} \sqrt{10x ^{6}}$

33. anonymous

i got $2x ^{4} \sqrt{5}$

You seem to have the hang of it!

35. anonymous

so its right ? :)

It is the same as what I got. So I think it is right.

37. anonymous

and its the same steps for addition ? for example $4^{3}\sqrt{a} + ^{3}\sqrt{64a}$

38. anonymous

i got $16^{3}\sqrt{a}$

39. anonymous

but im not sureee

Is that 4 cuberoot of a + cube root of 64a? If it is$4\sqrt[3]{a}+\sqrt[3]{64a}=8\sqrt[3]{a}$

41. anonymous

yes it is , your right . i got confused with it

You're doing fine, I've got to run. good luck

43. anonymous

thank youuuu ! :)