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anonymous

  • 5 years ago

1.) 6 sqrt.5 ( [srt.11] + [sqrt.5] ) 2.) (3 sqrt.3 +3 )(6 sqrt. 3 + 2)

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  1. anonymous
    • 5 years ago
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    1.) \[6\sqrt{5} ( \sqrt{11} + \sqrt{5})\]

  2. amistre64
    • 5 years ago
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    what do you come up with when you distribute it thru?

  3. anonymous
    • 5 years ago
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    2.) \[(3\sqrt{3} + 3) (6\sqrt{3} + 2)\]

  4. anonymous
    • 5 years ago
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    what do you mean ?

  5. amistre64
    • 5 years ago
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    I mean that you need to know what the distributive property is so you can solve these for yourself ;)

  6. amistre64
    • 5 years ago
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    if you want to learn, I can teach you :)

  7. amistre64
    • 5 years ago
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    and posting 2 questions at a time tends to mean you just want someone else to do your homework for you.....

  8. anonymous
    • 5 years ago
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    \[2.) 6 + 18\sqrt{3}^{2} + 6\sqrt{3} \]

  9. anonymous
    • 5 years ago
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    i think thats the answer

  10. anonymous
    • 5 years ago
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    and no its not homework its an exam for my course

  11. amistre64
    • 5 years ago
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    its a good start.... but lets check it out...

  12. anonymous
    • 5 years ago
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    i dont think i can simplify it more ?

  13. amistre64
    • 5 years ago
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    (3 sqrt.3 +3 )(6 sqrt. 3 + 2) 3sqrt(3) (6sqrt(3)) = 18(3) 3(2)sqrt(3) = 6sqrt(3) 3(6sqrt(3)) = 18sqrt(3) 3(2)=6

  14. anonymous
    • 5 years ago
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    so im right ? :)

  15. amistre64
    • 5 years ago
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    54+6 +24sqrt(3) 60 + 24sqrt(3) if I did it right :)

  16. amistre64
    • 5 years ago
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    you had 3 terms good, but were missing that forth

  17. amistre64
    • 5 years ago
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    12(5 + 2sqrt(3)) is another way to write it

  18. anonymous
    • 5 years ago
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    ohhh true ! and for the 1st problem i got \[6\sqrt{11} + 5\]

  19. anonymous
    • 5 years ago
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    im not sure if its right ?

  20. amistre64
    • 5 years ago
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    I got: 6sqrt(55) + 30

  21. amistre64
    • 5 years ago
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    \[6\sqrt{5*11} + 6\sqrt{5*5}\]

  22. anonymous
    • 5 years ago
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    ahhh true , i thought i was just suppose to cancel it out

  23. amistre64
    • 5 years ago
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    \[6\sqrt{55} + 6(5) = 6\sqrt{55}+30\]

  24. anonymous
    • 5 years ago
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    \[(2x \sqrt{12x}) (3\sqrt{4x})\]

  25. anonymous
    • 5 years ago
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    can you help me with that problem aswell ?

  26. anonymous
    • 5 years ago
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    i got \[24x ^{2}\sqrt{3}\]

  27. amistre64
    • 5 years ago
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    multiplication doesnt care in what order you do it...\[2x(3) *\sqrt{12x}*\sqrt{4x} = 6x \sqrt{48x^2}\]

  28. anonymous
    • 5 years ago
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    cant i simplify that further ?

  29. amistre64
    • 5 years ago
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    6x 4x sqrt(3) 24x^2 sqrt(3)

  30. anonymous
    • 5 years ago
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    same as my answer ?

  31. amistre64
    • 5 years ago
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    you were right :)

  32. anonymous
    • 5 years ago
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    thank youuu :) i had to double check ! :D how about this one : \[\sqrt{2x ^{2}} \sqrt{10x ^{6}}\]

  33. anonymous
    • 5 years ago
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    i got \[2x ^{4} \sqrt{5}\]

  34. radar
    • 5 years ago
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    You seem to have the hang of it!

  35. anonymous
    • 5 years ago
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    so its right ? :)

  36. radar
    • 5 years ago
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    It is the same as what I got. So I think it is right.

  37. anonymous
    • 5 years ago
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    and its the same steps for addition ? for example \[4^{3}\sqrt{a} + ^{3}\sqrt{64a}\]

  38. anonymous
    • 5 years ago
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    i got \[16^{3}\sqrt{a}\]

  39. anonymous
    • 5 years ago
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    but im not sureee

  40. radar
    • 5 years ago
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    Is that 4 cuberoot of a + cube root of 64a? If it is\[4\sqrt[3]{a}+\sqrt[3]{64a}=8\sqrt[3]{a}\]

  41. anonymous
    • 5 years ago
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    yes it is , your right . i got confused with it

  42. radar
    • 5 years ago
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    You're doing fine, I've got to run. good luck

  43. anonymous
    • 5 years ago
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    thank youuuu ! :)

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