anonymous
  • anonymous
1.) 6 sqrt.5 ( [srt.11] + [sqrt.5] ) 2.) (3 sqrt.3 +3 )(6 sqrt. 3 + 2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1.) \[6\sqrt{5} ( \sqrt{11} + \sqrt{5})\]
amistre64
  • amistre64
what do you come up with when you distribute it thru?
anonymous
  • anonymous
2.) \[(3\sqrt{3} + 3) (6\sqrt{3} + 2)\]

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anonymous
  • anonymous
what do you mean ?
amistre64
  • amistre64
I mean that you need to know what the distributive property is so you can solve these for yourself ;)
amistre64
  • amistre64
if you want to learn, I can teach you :)
amistre64
  • amistre64
and posting 2 questions at a time tends to mean you just want someone else to do your homework for you.....
anonymous
  • anonymous
\[2.) 6 + 18\sqrt{3}^{2} + 6\sqrt{3} \]
anonymous
  • anonymous
i think thats the answer
anonymous
  • anonymous
and no its not homework its an exam for my course
amistre64
  • amistre64
its a good start.... but lets check it out...
anonymous
  • anonymous
i dont think i can simplify it more ?
amistre64
  • amistre64
(3 sqrt.3 +3 )(6 sqrt. 3 + 2) 3sqrt(3) (6sqrt(3)) = 18(3) 3(2)sqrt(3) = 6sqrt(3) 3(6sqrt(3)) = 18sqrt(3) 3(2)=6
anonymous
  • anonymous
so im right ? :)
amistre64
  • amistre64
54+6 +24sqrt(3) 60 + 24sqrt(3) if I did it right :)
amistre64
  • amistre64
you had 3 terms good, but were missing that forth
amistre64
  • amistre64
12(5 + 2sqrt(3)) is another way to write it
anonymous
  • anonymous
ohhh true ! and for the 1st problem i got \[6\sqrt{11} + 5\]
anonymous
  • anonymous
im not sure if its right ?
amistre64
  • amistre64
I got: 6sqrt(55) + 30
amistre64
  • amistre64
\[6\sqrt{5*11} + 6\sqrt{5*5}\]
anonymous
  • anonymous
ahhh true , i thought i was just suppose to cancel it out
amistre64
  • amistre64
\[6\sqrt{55} + 6(5) = 6\sqrt{55}+30\]
anonymous
  • anonymous
\[(2x \sqrt{12x}) (3\sqrt{4x})\]
anonymous
  • anonymous
can you help me with that problem aswell ?
anonymous
  • anonymous
i got \[24x ^{2}\sqrt{3}\]
amistre64
  • amistre64
multiplication doesnt care in what order you do it...\[2x(3) *\sqrt{12x}*\sqrt{4x} = 6x \sqrt{48x^2}\]
anonymous
  • anonymous
cant i simplify that further ?
amistre64
  • amistre64
6x 4x sqrt(3) 24x^2 sqrt(3)
anonymous
  • anonymous
same as my answer ?
amistre64
  • amistre64
you were right :)
anonymous
  • anonymous
thank youuu :) i had to double check ! :D how about this one : \[\sqrt{2x ^{2}} \sqrt{10x ^{6}}\]
anonymous
  • anonymous
i got \[2x ^{4} \sqrt{5}\]
radar
  • radar
You seem to have the hang of it!
anonymous
  • anonymous
so its right ? :)
radar
  • radar
It is the same as what I got. So I think it is right.
anonymous
  • anonymous
and its the same steps for addition ? for example \[4^{3}\sqrt{a} + ^{3}\sqrt{64a}\]
anonymous
  • anonymous
i got \[16^{3}\sqrt{a}\]
anonymous
  • anonymous
but im not sureee
radar
  • radar
Is that 4 cuberoot of a + cube root of 64a? If it is\[4\sqrt[3]{a}+\sqrt[3]{64a}=8\sqrt[3]{a}\]
anonymous
  • anonymous
yes it is , your right . i got confused with it
radar
  • radar
You're doing fine, I've got to run. good luck
anonymous
  • anonymous
thank youuuu ! :)

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