how do you simplify
2a^2+5a-3??

- anonymous

how do you simplify
2a^2+5a-3??

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- amistre64

may be it means to put it into its counterpart... y = M(x-h)^2 +k ?

- anonymous

well the whole equation is
16a^4-1/2a^2+5a-3 * 2a^2+9a+9/4a^2+1

- anonymous

You have to factor it: \[2a^2+5a-3\]
You get \[(2a^2)(-a-3)\]
Then: \[2a(a+3) -1(a+3)\]
Finally: \[(2a-1)(a+3)\]

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## More answers

- amistre64

\[\frac{16x^4 -1}{2a^2 +5a -3} * \frac{2a^2 +9a +9}{4a^2 +1}\]

- anonymous

you people are a bit confusing- i mean that you're making it more complicated

- anonymous

Yeah, amistre, that's totally irrelevant. It's a quadratic equation; all you have to do is factor it.

- anonymous

so far I have
(4a^2+1)(2a+1)(2a-1)/(2a+?) * (2a+9)(a+1)/(4a^2+a)

- amistre64

lol....well it helps to know what the actual question is :)

- amistre64

how do YOU simplify 2x^2 +5a -3 ?? lol

- anonymous

yeah lol that was my question

- anonymous

yes, but not is you're making it more complicated
you;re just adding mroe steps

- anonymous

She/he asked for \[2a2+5a−3\] to be simplified. That means factoring it into binomials.

- anonymous

she

- amistre64

i didnt add any steps... I simply was wondering what it was talking about to begin with. right?

- anonymous

\[2a^2+5a−3\] should be the equation; my bad.

- anonymous

I just need that to be factored so I can simplify the rest of the problem

- anonymous

Please read the steps that I posted previously, and tell me if it helps at all.

- anonymous

not really. It only makes it more confusing.

- amistre64

in the context of the rest of the "question", then yes; factoring it is appropriate.

- amistre64

i dont see it factoring to anything useful; so factor the difference of cubes and leave that part alone ;)

- anonymous

Ok thanks :D

- amistre64

you get square roots involved if you factor that thing there, and the other one is clean of them....so they dont cancel anyways... make sense?

- anonymous

A little more than it did. This is what I got:
(2a-1)(2a+1)(2a+9)(a+1)/2a^2+5a-3

- amistre64

without doing the math myself, that looks about right :)

- anonymous

Awesome lol thank you

- amistre64

x = -5/4 +- 7/4
x = 12/4 = 3
x = -2/4 = -1/2
(2x-1)(x+3) .... or this :)

- amistre64

(x+6/2)(x-1/2)
(x+3)(2x-1) is right... now that I have a moment to see it correctly ;)

- anonymous

That's what I thought it was. Except I had the signs switched.

- amistre64

(2a-1)(2a+1)(2a+9)(a+1)
---------------------
(2a-1)(a+3)

- amistre64

2a^2 +9a +9
(a+6/2)(a+3/2)
(a+3)(2a+3) is what I get on the top over there

- anonymous

so the answer would be:
\[(2a+1)(2a+9)(a+1)\div (a+3)\]

- amistre64

(a+3)(2a+3) (4x^2+1) (4x^2-1)
----------- ----------------
(2a-1)(a+3) (4x^2+1)
(2a+3) (4a^2-1)
---------------
(2a-1)
(2a+3) (2a-1)(2a+1)
---------------
(2a-1)
(2a+3)(2a+1)

- anonymous

how did you get a+3 on the top?

- amistre64

4a^2 +8a +3 is what I get if I did it right ;)
(a+3)(2a+3) = 2a^2 +9a +9

- amistre64

(a+6/2)(a+3/2)
(a+3) (a+3/2)
(a+3)(2a+3)

- anonymous

but when you factor it back to 2a^2+9a+9...the 3's don't add up to 9

- amistre64

2aa + 3a +2(3)a + 9
2a^2 +3a +6a +9
2a^2 +9a +9

- anonymous

Ooooh ok I think I got

- amistre64

am I right :)

- anonymous

Yup!! Thanks! Now I have 4 more to go....jeez

- amistre64

lol good luck ;)

- anonymous

thanks

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