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anonymous
 5 years ago
how do you simplify
2a^2+5a3??
anonymous
 5 years ago
how do you simplify 2a^2+5a3??

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0may be it means to put it into its counterpart... y = M(xh)^2 +k ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well the whole equation is 16a^41/2a^2+5a3 * 2a^2+9a+9/4a^2+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to factor it: \[2a^2+5a3\] You get \[(2a^2)(a3)\] Then: \[2a(a+3) 1(a+3)\] Finally: \[(2a1)(a+3)\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{16x^4 1}{2a^2 +5a 3} * \frac{2a^2 +9a +9}{4a^2 +1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you people are a bit confusing i mean that you're making it more complicated

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, amistre, that's totally irrelevant. It's a quadratic equation; all you have to do is factor it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so far I have (4a^2+1)(2a+1)(2a1)/(2a+?) * (2a+9)(a+1)/(4a^2+a)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol....well it helps to know what the actual question is :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how do YOU simplify 2x^2 +5a 3 ?? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah lol that was my question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, but not is you're making it more complicated you;re just adding mroe steps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0She/he asked for \[2a2+5a−3\] to be simplified. That means factoring it into binomials.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i didnt add any steps... I simply was wondering what it was talking about to begin with. right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2a^2+5a−3\] should be the equation; my bad.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just need that to be factored so I can simplify the rest of the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Please read the steps that I posted previously, and tell me if it helps at all.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not really. It only makes it more confusing.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0in the context of the rest of the "question", then yes; factoring it is appropriate.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i dont see it factoring to anything useful; so factor the difference of cubes and leave that part alone ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you get square roots involved if you factor that thing there, and the other one is clean of them....so they dont cancel anyways... make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A little more than it did. This is what I got: (2a1)(2a+1)(2a+9)(a+1)/2a^2+5a3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0without doing the math myself, that looks about right :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Awesome lol thank you

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x = 5/4 + 7/4 x = 12/4 = 3 x = 2/4 = 1/2 (2x1)(x+3) .... or this :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x+6/2)(x1/2) (x+3)(2x1) is right... now that I have a moment to see it correctly ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's what I thought it was. Except I had the signs switched.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(2a1)(2a+1)(2a+9)(a+1)  (2a1)(a+3)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02a^2 +9a +9 (a+6/2)(a+3/2) (a+3)(2a+3) is what I get on the top over there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the answer would be: \[(2a+1)(2a+9)(a+1)\div (a+3)\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(a+3)(2a+3) (4x^2+1) (4x^21)   (2a1)(a+3) (4x^2+1) (2a+3) (4a^21)  (2a1) (2a+3) (2a1)(2a+1)  (2a1) (2a+3)(2a+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get a+3 on the top?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04a^2 +8a +3 is what I get if I did it right ;) (a+3)(2a+3) = 2a^2 +9a +9

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(a+6/2)(a+3/2) (a+3) (a+3/2) (a+3)(2a+3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but when you factor it back to 2a^2+9a+9...the 3's don't add up to 9

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02aa + 3a +2(3)a + 9 2a^2 +3a +6a +9 2a^2 +9a +9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ooooh ok I think I got

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yup!! Thanks! Now I have 4 more to go....jeez
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