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anonymous

  • 5 years ago

does (2x+15)(x-2)=2x^2+13x+15

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  1. anonymous
    • 5 years ago
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    15(2) = 30 ..NOT 15...so I would have to say no

  2. anonymous
    • 5 years ago
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    I just got that...

  3. anonymous
    • 5 years ago
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    you typoed or else its wrong lol

  4. anonymous
    • 5 years ago
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    how do you get thirteen?

  5. anonymous
    • 5 years ago
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    No I just got that it was wrong lol

  6. anonymous
    • 5 years ago
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    id be 15x-4x if anything and even that's bad....

  7. anonymous
    • 5 years ago
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    FOIL the thing out dude :)

  8. anonymous
    • 5 years ago
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    I don't think that's right.

  9. anonymous
    • 5 years ago
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    I tried. I hate algebra lol

  10. anonymous
    • 5 years ago
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    (2x+15)(x-2) 2x(x) + 2x(-2) +15(x) +15(-2)

  11. anonymous
    • 5 years ago
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    2x^2 -4x +15x -30 2x^2 +11x -30

  12. anonymous
    • 5 years ago
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    then wouldn't it be using 10 and 3?

  13. anonymous
    • 5 years ago
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    would what be using 10 and 3 ? what would make it true you mean?

  14. anonymous
    • 5 years ago
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    yeah lol

  15. anonymous
    • 5 years ago
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    never mind

  16. anonymous
    • 5 years ago
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    what are the factor of 15? 1,15 3,5 thats your options right there if you want integer answers.

  17. anonymous
    • 5 years ago
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    that's wrong too

  18. anonymous
    • 5 years ago
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    well what I said

  19. anonymous
    • 5 years ago
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    15+1 = 16 3+5 =8...so you dont get a right answer lol

  20. anonymous
    • 5 years ago
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    Well what my teacher taught us to multiply the end numbers and factor the number from that

  21. anonymous
    • 5 years ago
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    i hate shortcuts as answers, unless you understand the mechanics of what is going on in the problem; shortcuts just confuse the issue.

  22. anonymous
    • 5 years ago
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    distribute the equations thru...

  23. anonymous
    • 5 years ago
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    tell me: what does it mean to distribute?

  24. anonymous
    • 5 years ago
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    a(b+c) = ?? a(b) + a(c) right?

  25. anonymous
    • 5 years ago
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    I know what it means. This review for us. I just don't remember any of it.

  26. anonymous
    • 5 years ago
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    did i just "distribute" that a thru the paranthesis?

  27. anonymous
    • 5 years ago
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    yes

  28. anonymous
    • 5 years ago
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    (f+l) (m+n) distribute the first into the last there: (f+l)(m) + (f+l)(n) Now distribute again :) f(m) + l(m) + f(n) + l(n)

  29. anonymous
    • 5 years ago
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    that is HOW you solve the problem....the shortcut is FOIL or whatever acronym they feel like using...

  30. anonymous
    • 5 years ago
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    when you forget the shortcuts, use the actual process ;)

  31. anonymous
    • 5 years ago
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    ok, thanks lol

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