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kirbykirby

  • 5 years ago

For any 2 vectors a,b the cross product "(3a + 2b) x a" is the same vector as: a) 2a x b b) 2b x a c) 3a x b d) 3b x a e) 5b x a

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  1. amistre64
    • 5 years ago
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    is cross product the same as dot product?

  2. amistre64
    • 5 years ago
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    i see that they arent.... i was sooo close lol

  3. kirbykirby
    • 5 years ago
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    yeah they aren't the same

  4. amistre64
    • 5 years ago
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    is cross priduct orthogonal? they perpendicular to each other then?

  5. kirbykirby
    • 5 years ago
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    yeah

  6. amistre64
    • 5 years ago
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    i was just reading up on vectors last night... if 2 vectors are othogonal, they have -1 as the product of their slopes... we wouldnt happen to know the vector quantities would we...

  7. kirbykirby
    • 5 years ago
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    no, the question I asked is really all the information given :(

  8. amistre64
    • 5 years ago
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    ||a x b ||^2 = ||a||^2 ||b||^2 - (a.b)^2...does that help us any? :)

  9. kirbykirby
    • 5 years ago
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    is that like the law of cosines? o_O

  10. amistre64
    • 5 years ago
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    3<xa,ya> + 2<xb,yb> <3xa+2xb , 3ya + 2yb> right? lol.....wish I knew

  11. amistre64
    • 5 years ago
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    would it be asking this then? <3xa+2xb , 3ya + 2yb> (x) <xa,yx>

  12. kirbykirby
    • 5 years ago
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    oh perhaps

  13. kirbykirby
    • 5 years ago
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    well actually i think i'd need to add the z-component, since we'd get a 3-D vector

  14. amistre64
    • 5 years ago
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    i gots no idea how to add a z component in there ;)

  15. amistre64
    • 5 years ago
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  16. kirbykirby
    • 5 years ago
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    what would 3a x a = ? is it still a vector a multiplied by smtg?

  17. kirbykirby
    • 5 years ago
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    oh wait it would be 0 right o_o

  18. amistre64
    • 5 years ago
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    cant recall :) do you know where this mystery vector is supposed to be attached? I got this so far...but I may be wrong.

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  19. kirbykirby
    • 5 years ago
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    ohh I figured it out! :) haha. Ok i wasn't sure but there's the property that (3a + 2b) x a = 3a x a + 2b x a = 0 + 2b x a... omg -_-

  20. amistre64
    • 5 years ago
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    thats a nice property to know then ;) good job!

  21. kirbykirby
    • 5 years ago
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    oye our prof never showed it to us :( Lol glad that was actually easy now xD thx for ur help nevertheless :)

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spraguer (Moderator)
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