kirbykirby
  • kirbykirby
For any 2 vectors a,b the cross product "(3a + 2b) x a" is the same vector as: a) 2a x b b) 2b x a c) 3a x b d) 3b x a e) 5b x a
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

kirbykirby
  • kirbykirby
For any 2 vectors a,b the cross product "(3a + 2b) x a" is the same vector as: a) 2a x b b) 2b x a c) 3a x b d) 3b x a e) 5b x a
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

amistre64
  • amistre64
is cross product the same as dot product?
amistre64
  • amistre64
i see that they arent.... i was sooo close lol
kirbykirby
  • kirbykirby
yeah they aren't the same

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
is cross priduct orthogonal? they perpendicular to each other then?
kirbykirby
  • kirbykirby
yeah
amistre64
  • amistre64
i was just reading up on vectors last night... if 2 vectors are othogonal, they have -1 as the product of their slopes... we wouldnt happen to know the vector quantities would we...
kirbykirby
  • kirbykirby
no, the question I asked is really all the information given :(
amistre64
  • amistre64
||a x b ||^2 = ||a||^2 ||b||^2 - (a.b)^2...does that help us any? :)
kirbykirby
  • kirbykirby
is that like the law of cosines? o_O
amistre64
  • amistre64
3 + 2 <3xa+2xb , 3ya + 2yb> right? lol.....wish I knew
amistre64
  • amistre64
would it be asking this then? <3xa+2xb , 3ya + 2yb> (x)
kirbykirby
  • kirbykirby
oh perhaps
kirbykirby
  • kirbykirby
well actually i think i'd need to add the z-component, since we'd get a 3-D vector
amistre64
  • amistre64
i gots no idea how to add a z component in there ;)
amistre64
  • amistre64
1 Attachment
kirbykirby
  • kirbykirby
what would 3a x a = ? is it still a vector a multiplied by smtg?
kirbykirby
  • kirbykirby
oh wait it would be 0 right o_o
amistre64
  • amistre64
cant recall :) do you know where this mystery vector is supposed to be attached? I got this so far...but I may be wrong.
1 Attachment
kirbykirby
  • kirbykirby
ohh I figured it out! :) haha. Ok i wasn't sure but there's the property that (3a + 2b) x a = 3a x a + 2b x a = 0 + 2b x a... omg -_-
amistre64
  • amistre64
thats a nice property to know then ;) good job!
kirbykirby
  • kirbykirby
oye our prof never showed it to us :( Lol glad that was actually easy now xD thx for ur help nevertheless :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.