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anonymous
 5 years ago
rationalize denominator : please help
1.) 4/ sqrt. 7p
2.) srqt.98/x
3.) 9/3 sqrt.y
4.) sqrt.7 / sqrt.5 +7
anonymous
 5 years ago
rationalize denominator : please help 1.) 4/ sqrt. 7p 2.) srqt.98/x 3.) 9/3 sqrt.y 4.) sqrt.7 / sqrt.5 +7

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01.) \[4/ \sqrt{7p}\] 2.) \[\sqrt{98}/x\] 3.) \[9/ 3\sqrt{y}\] 4.) \[\sqrt{7}/ \sqrt{5} + 7\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0please hlep , i dont understand them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok the idea is to get the sqrt out of the denominator For 1) multiply by sqrt(7p)/sqrt(7p)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(x) * sqrt(x) = x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.07p everything within the radical sorry imagine if i said x = 7p >4*sqrt(7p)/7p that is the rationalised form for the first one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For number 4 you have to use a conjugate which is basically the denominator except you flip the sign >sqrt(5)7 multiply this on top and bottom by distributing (using FOIL) and the sqrts in denominator will go away

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0number 2 is already rationalised but you can simplify sqrt(98) by factoring out a perfect square number 3 can be done same way as num 1, dont forget to reduce hope this helps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how would it be done ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and thank you for helping , im just really bad in math

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which part are you stuck on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all of it , especially foil

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok lets look at num 2 since there is no sqrt in denominator, we don't have to do anything there but we can simplify sqrt(98) Factors of 98 = 2*49 =2*7*7 rewrite sqrt(98) as sqrt(2)*sqrt(7)*sqrt(7) remember sqrt(7)*sqrt(7) = 7 leaving 7sqrt(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for number one i got : 4sqrt.7p/7p ? correct ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.07sqrt(2)/x sorry no the x doesnt change it stays on the bottom

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for num 3 we want to get rid of sqrt(y) by multiplying by sqrt(y) on top and bottom >9/3sqrt(y) * sqrt(y)/sqrt(y) = 9sqrt(y)/3y Now reduce what does 9/3 reduce to?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or would 7p cancel itself ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0correct ohh no the 7p wouldnt cancel because the one on top is inside the sqrt, that is important

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0answer for 3) is 3sqrt(y)/y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh no your answer for 3 is wrong , it doesnt come out in my exam as an option

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm maybe the sqrt is in the numerator try 3sqrt(y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is no 3 , only 9 sqrt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm maybe the sqrt is in the numerator try 3sqrt(y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0interesting, what are the possible answers they give

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0number 3 : A) 9^3 sqrt.y^2 /y b.) 9y c.) 9^3 sqrt. y^2 d.) 9^3 sqrt. y /y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and your sure the question was 9/(3sqrt(y))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it better view higher above ^^^^ with the equation button

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all the way up^^^^^^^^^^^^^^^^^^^^^^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well in that case the answer is 3sqrt(y)/y i'd bet on d) , weird you might have to talk to teacher on this one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and for the rest of the problems ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well what about the first 2 are those answers available :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how to solve this though ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rationalise fractions with sq roots? yes i know how to solve those but maybe they're looking for something else look at prev examples and see if it lines up with what i've shown

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0correction : \[9 / ^{3} \sqrt{y}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it changes everything ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0little bit the answer is A think of it now as fractional exponents cube root of y = y^(1/3) to cancel that we multiply top and bottom by y^2/3 >y^1/3 * y^2/3 = y (add the exponents) leaving (9*y^2/3)/y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you mean : 9^3 sqrt.y^2 / y ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh y^2/3 can be written as cube root of y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank youuu ! its so complicated to me. and the rest ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh yes FOIL is just way to remember how to distribute. what is result of (x+2)*(x3)? _>distribute the x to both the x and 3 >x*x + x*3 = x^2  3x >then distribute the 2 to the x and 3 >2*x + 2*3 = 2x 6 put it together >x^2 3x +2x 6 = x^2 x 6 make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is there an easier way ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have to use (x+2)*(x3) in the equation to cancel out sqrt ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no that was just an example and not really you still have to do the multiplications For this problem we would be multiplying (sqrt(5)+7) * (sqrt(5)  7)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i gotta go the answer is (7sqrt(7)  sqrt(35))/44 try to figure it out on your own by multiplying what i put above for denominator then multiply sqrt(7)*(sqrt(5)7) for numerator Then at the end you have to distribute a negative by flipping the signs good luck
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