anonymous
  • anonymous
Factor x3 + 2x2 + 5x + 10
Mathematics
katieb
  • katieb
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amistre64
  • amistre64
well this ones tricker, you have to do more of a trial and error to break apart the "^3" cubic part.
amistre64
  • amistre64
we can increase our odds by taking the factors of 10 as a pool of numbers to test. 1,10; 2,5 I use synthetic division to test it becasue its just less clutter
amistre64
  • amistre64
lets try x = -1: -1| 1 2 5 10 0 -1 -1 -4 ----------- 1 1 4 6 <- not a zero, not a factor

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amistre64
  • amistre64
x = -2 maybe? -2| 1 2 5 10 0 -2 0 -10 ----------- 1 0 5 0 <- zero!! we have a winner..
amistre64
  • amistre64
(x+2)(x^2+5x)
amistre64
  • amistre64
opps...silly superhero.... (x+2) (x^2+5)
anonymous
  • anonymous
Try factoring by grouping. x^3 + 2x^2 + 5x + 10 x^2(x+2)+5(x+2) (x^2+5)(x+2)
anonymous
  • anonymous
lol
amistre64
  • amistre64
hey grouping does work with this one.... that was cool ;)
amistre64
  • amistre64
of course its not as brainiacal as mine...but you know ;)
anonymous
  • anonymous
yes lol
anonymous
  • anonymous
9x2 + 48x + 64

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