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anonymous

  • 5 years ago

rationalize denominator : please help 1.) 4/ sqrt. 7p 2.) srqt.98/x 3.) 9/3 sqrt.y 4.) sqrt.7 / sqrt.5 +7

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  1. anonymous
    • 5 years ago
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    1.) 4/7p−−√ 2.) 98−−√/x 3.) 9/3y√ 4.) 7√/5√+7

  2. anonymous
    • 5 years ago
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    \[1.) 4/\sqrt{7p}\]

  3. anonymous
    • 5 years ago
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    2.) \[\sqrt{98}/x\]

  4. anonymous
    • 5 years ago
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    The denominator is not supposed to have a square root. So when you rationalize you get rid of the square root in the denominator by multiplying the numerator and denominator by the square root, which is essentially multiplying by 1 so it doesnt change the value of the expression.

  5. anonymous
    • 5 years ago
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    3.) \[9/^{3}\sqrt{y}\]

  6. anonymous
    • 5 years ago
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    4.) \[\sqrt{7} / \sqrt{5} + 7\]

  7. dumbcow
    • 5 years ago
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    haha thats why its a cubed root, not 9/3

  8. anonymous
    • 5 years ago
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    yes i sent you the correction in the other post

  9. anonymous
    • 5 years ago
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    xavier : so i take out the sqrt ?

  10. anonymous
    • 5 years ago
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    LIke for 4/sqrt(7p). Multiply the numerator and denominator by sqrt(7p). So the denominator gets "rationalized" because sqrt(7p)*sqrt(7p) is simply 7p.

  11. anonymous
    • 5 years ago
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    so the answer would be : 4 sqr.7p ? or 4sqrt.7p/7p ?

  12. anonymous
    • 5 years ago
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    or ?

  13. anonymous
    • 5 years ago
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    4sqrt(7p)/7p

  14. anonymous
    • 5 years ago
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    and fot the second one ? would it be 7sqrt.2x ? or 7sqrt. 2/x ?

  15. anonymous
    • 5 years ago
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    \[7 \sqrt{2x} , 7 \sqrt{2/x}\]

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