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anonymous
 5 years ago
4200 ft. apart with height of 546 ft above roadway...cable is 15ft above roadway...I have vertex at (0,15) and (2100, 546) , (2100, 546) but can't get equation to work
anonymous
 5 years ago
4200 ft. apart with height of 546 ft above roadway...cable is 15ft above roadway...I have vertex at (0,15) and (2100, 546) , (2100, 546) but can't get equation to work

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0gonna have to chase the question am i...... stay put! lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0those are some awfully big number, this could get messy :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes I've worked it out several times

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your values are good... (2100^2)a +(2100)b + c = 546 (2100^2)a (2100)b + c = 546 0a +0b + c = 15 we see the c = 15 here right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(2100^2)a +(2100)b + cc = 546 15 (2100^2)a +(2100)b = 531 (2100^2)a (2100)b + cc = 54615 (2100^2)a (2100)b = 531  531 2100b a =  (2100)^2 substitute this into the next equation right? (2100^2)a +(2100)b = 531 

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(2100^2)(531 2100b)  (2100)b = 531 (2100)^2 531 2100b  2100b = 531 it says b = 0 :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0which is what you would expect it to be since we are on the y axis already and just raised by 15 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we are using yy1=c(xx1)2 yes, yintercept is (0, 15)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0531 a =  (2100)^2 \[y = \frac{531}{2100^2} x^2 + 15\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when x = 2100 we get: 531 + 15 = 546 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0come on..you know im right....tell me i did good :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was squaring 2100 and got lost in math... YES you're right...AWESOME!!!! THANKS ALOT!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was comparing my work to yours...all different attempts , lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol...... thanx :) you had it tight to begin with, dont let the numbers scare you ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have time for another
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