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anonymous

  • 5 years ago

4200 ft. apart with height of 546 ft above roadway...cable is 15ft above roadway...I have vertex at (0,15) and (2100, 546) , (-2100, 546) but can't get equation to work

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  1. amistre64
    • 5 years ago
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    gonna have to chase the question am i...... stay put! lol

  2. amistre64
    • 5 years ago
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    those are some awfully big number, this could get messy :)

  3. anonymous
    • 5 years ago
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    yes I've worked it out several times

  4. amistre64
    • 5 years ago
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    your values are good... (2100^2)a +(2100)b + c = 546 (-2100^2)a -(2100)b + c = 546 0a +0b + c = 15 we see the c = 15 here right?

  5. amistre64
    • 5 years ago
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    (2100^2)a +(2100)b + c-c = 546 -15 (2100^2)a +(2100)b = 531 (-2100^2)a -(2100)b + c-c = 546-15 (2100^2)a -(2100)b = 531 --------------------------- 531 -2100b a = ----------- (2100)^2 substitute this into the next equation right? (2100^2)a +(2100)b = 531 ------------------------------

  6. amistre64
    • 5 years ago
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    (2100^2)(531 -2100b) -------------------- -(2100)b = 531 (2100)^2 531 -2100b - 2100b = 531 it says b = 0 :)

  7. amistre64
    • 5 years ago
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    which is what you would expect it to be since we are on the y axis already and just raised by 15 right?

  8. anonymous
    • 5 years ago
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    so we are using y-y1=c(x-x1)2 yes, y-intercept is (0, 15)

  9. amistre64
    • 5 years ago
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    531 a = ---------- (2100)^2 \[y = \frac{531}{2100^2} x^2 + 15\]

  10. amistre64
    • 5 years ago
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    see if this fits :)

  11. amistre64
    • 5 years ago
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    when x = 2100 we get: 531 + 15 = 546 right?

  12. amistre64
    • 5 years ago
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    come on..you know im right....tell me i did good :)

  13. anonymous
    • 5 years ago
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    I was squaring 2100 and got lost in math... YES you're right...AWESOME!!!! THANKS ALOT!

  14. anonymous
    • 5 years ago
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    I was comparing my work to yours...all different attempts , lol

  15. amistre64
    • 5 years ago
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    lol...... thanx :) you had it tight to begin with, dont let the numbers scare you ;)

  16. anonymous
    • 5 years ago
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    Thanks!

  17. anonymous
    • 5 years ago
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    you have time for another

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