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anonymous

  • 5 years ago

√(x+4)-√(x+1)=1

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  1. anonymous
    • 5 years ago
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    trying to solve for x?

  2. anonymous
    • 5 years ago
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    the answer is supposed to be x=0 but I don't know why

  3. anonymous
    • 5 years ago
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    Move one radical to the other side of the equation and then square each side. Remember that the right side will be a binomial so you will need to FOIL it. You will get a radical in the product so you will need to isolate it and solve it the same way by squaring each side.

  4. anonymous
    • 5 years ago
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    so when you move the radical over, your new equation is: √(x+4)=1+√(x+1)

  5. anonymous
    • 5 years ago
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    Yup. Now square each side. FOIL the right side.

  6. anonymous
    • 5 years ago
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    the left side just "pops" out as x+4?

  7. anonymous
    • 5 years ago
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    yes. lovely isn't it?

  8. anonymous
    • 5 years ago
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    yes, I'm making it overly complicated.

  9. anonymous
    • 5 years ago
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    you'll get this and then combine like terms and isolate the radical again. \[x+4=x+1+2\sqrt{(x+1)} + 1\]

  10. anonymous
    • 5 years ago
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    I'm afraid you lost me again.

  11. anonymous
    • 5 years ago
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    This is what you get when you square both sides.

  12. anonymous
    • 5 years ago
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    but then if you tried to get stuff over on the left, your x disappears...

  13. anonymous
    • 5 years ago
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    It's OK because you still have one under the radical. Did you get \[2=2\sqrt{(x+1)}\]

  14. anonymous
    • 5 years ago
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    yes, then do you get 4=4(x+1)?

  15. anonymous
    • 5 years ago
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    I would've divided both sides by 2 first, but you'll still get x=0 in the end.

  16. anonymous
    • 5 years ago
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    alright, let me try it that way then...I did not get to 0....

  17. anonymous
    • 5 years ago
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    YES!! Got it! Thank you so much for the step by step!!

  18. anonymous
    • 5 years ago
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    After dividing both sides by 2, you'll get \[1=\sqrt{(x+1)}\]

  19. anonymous
    • 5 years ago
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    YAY! Good luck!

  20. anonymous
    • 5 years ago
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    Lifesaver!

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