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r=r...cos(theta) = 1-cos(theta)...2cos(theta)=1...cos(theta)=(1/2)...cos^-1(1/2)=pi/3...

whats with the ....?

polar solutions eh...

ya polar (r, (theta))

cos(t) = 1-cos(t)
2cos(t) = 1

yup and u get 1/2 = r

so its a 60 degree angle and if u go to 360 its also the 300 degree angle?

120 doesn't work cuz then it would be -1/2

lol..... yeah, my stupidity there :)

sooo the r either way is 1/2 and then its just the 60 and 300 but in radian form??

cos^1(1/2)=your answer

since -r is the same but pi off, there might be more solutions....

*cos^-1(1/2)=your answer

(-1/2,120) would be a solution right?

it cant... since r is positive 1/2 not negative but that is a legit answer if that was needed

same as 240 would be too

well i got another quick question just like this one... r=cos3(theta) and r = sin3(theta)

if you set them eqaul to one another you ill get 1=tan3(theta)

cos and sin are equal at 45 degrees; so I would gander it has to do with muliples of 45/3

actually i have the answers for this too and its (pi/12) (5pi/12) and (9pi/12)

pi/12 is 15 degrees right?

correct

15(3) = 45...yay!! I was close to being right lol

oh boy not sure if i should congratz u on that or a lucky guess. alright what bout the others tho

15(5) = 75 got no idea about this one lol
15(9) = 135 = 90+45 Q2

ya those are all right but how the hey are u pulling them out of no where?

if I knew what the voices in my head were hiding from me..id be alooooot smarter ;)

haha alright i understand. i have that prob too so i hear ya out on that