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anonymous
 5 years ago
Multiple Choice:
An equation for a tangent to the graph of y=archsin (x/2) at the origin is
(a) x2y=0
(b) xy=0
(c) x=0
(d) y=0
(e) pix2y=0
anonymous
 5 years ago
Multiple Choice: An equation for a tangent to the graph of y=archsin (x/2) at the origin is (a) x2y=0 (b) xy=0 (c) x=0 (d) y=0 (e) pix2y=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just arcsin* btw.. hehe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0find the derivative then substitute 0,0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0derivative of arcsin is 1/(sqrt 1x^2) btw..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = sinh^1 y' = e^x  e^...../2........ something..... I know the other ones :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0oh...that "h" threw me. y' = 1/sqrt(1x^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats why i corrected him at top :P

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the equation to the tangent has the derivative as the slope.... 0 = f'(x)x + b

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0"y=archsin (x/2) at the origin" ack!!..... it helps to read the whole thing, I get lazy and start making up my own question lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0at 0,0 you get a slope of 1, so the equation of the tangent is: y = x and thats my final offer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lmao! i hope u put 0,0 in the derivative!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) I think I miss placed a Dx tho.... since its got that x/2 in there ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/ (\sqrt{2x} \sqrt{x+2}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[y' = \frac{Dx}{\sqrt{1\frac{x}{2}^2}} \rightarrow Dx = \frac{1}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats the derivative....forgot to close bracket lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I wanna change my vote :) y = x/2 ;) but I probably missed that one too

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol! ha this is bad... i dont like this question!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ack!! how can a fraction = 0 if its got a constant up top....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cuz the derivative of that equation will be the equation of the tangent slope...it cant be ny of those options :S...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0take this question, throw it in a sack, burn it in the fireplace, kill a chicken and spread its blood around the place to ward off any evil spirits that might rise from the ashes... ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0come to think of it, when does sin^1 have a hump in it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I thank you guys for all of the help! I can't exactly figure it out myself. Tricky tricky. tisk tisk. :)
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