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anonymous
 5 years ago
There is a frustum of a regular square pyramid for which "h" is the height, "a" is the length of a side of the lower base, "b" is the length of a side of the upper base, and "l" is the slant height. What is the area of its lower base?
anonymous
 5 years ago
There is a frustum of a regular square pyramid for which "h" is the height, "a" is the length of a side of the lower base, "b" is the length of a side of the upper base, and "l" is the slant height. What is the area of its lower base?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0area of lower base since its a square is a^2 upper base would be b^2 area of sides would be like trapezoids >each side area = (1/2)*l*(a+b)
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