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  • 5 years ago

There is a frustum of a regular square pyramid for which "h" is the height, "a" is the length of a side of the lower base, "b" is the length of a side of the upper base, and "l" is the slant height. What is the area of its lower base?

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  1. anonymous
    • 5 years ago
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    area of lower base since its a square is a^2 upper base would be b^2 area of sides would be like trapezoids ->each side area = (1/2)*l*(a+b)

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