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anonymous

  • 5 years ago

how do i find the area between f(x)= x^2+1 and g(x)= 11-x^2

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  1. dumbcow
    • 5 years ago
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    \[\int\limits_{a}^{b}(g(x) - f(x)) dx\]

  2. amistre64
    • 5 years ago
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    you need to have bounds; if the two cross paths you can use that, but an interval is usually stated.

  3. anonymous
    • 5 years ago
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    i found the bounds to be -sqrt(5) and sqrt(5) but when i put them into the integral equation, i get some crazy number that isn't right...

  4. anonymous
    • 5 years ago
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    Did you integrate yet?

  5. anonymous
    • 5 years ago
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    right now i have [(1/3)x^3+x]-[11x-(1/3)x^3] for the two integrals

  6. amistre64
    • 5 years ago
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    only do half of it; then double your answer

  7. anonymous
    • 5 years ago
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    what am i doing half of?

  8. dumbcow
    • 5 years ago
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    instead of integrating from -sqrt(5) to sqrt(5), integrate from 0 to sqrt(5) and then double your answer this is due to symmetry of parabolas

  9. dumbcow
    • 5 years ago
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    you have already done the integration just evaluate at sqrt(5) into what you posted above

  10. anonymous
    • 5 years ago
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    okay, thank you =)

  11. dumbcow
    • 5 years ago
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    your welcome

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