A. x = 2
B. x = 2.5
C. x = -1
D. x = 0.5

- anonymous

A. x = 2
B. x = 2.5
C. x = -1
D. x = 0.5

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- anonymous

So what's the question?

- anonymous

x^2-3x=-5/4 Which choices are solutions to the following equation?

- anonymous

Have you tried using the quadratic equation?

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## More answers

- anonymous

no how ?

- anonymous

this is the quadratic:\[-b \pm \sqrt{b ^{2}-4ac}/2a\]

- anonymous

is it -1

- anonymous

sorry it didnt come out right
http://en.wikipedia.org/wiki/Quadratic_equation

- anonymous

no its going to be two values

- anonymous

so you first want to set the given equation =0 kk? How do you do that?

- anonymous

yea -1 and 2

- anonymous

do wht .

- anonymous

\[x ^{2}-3x+5/4\]

- anonymous

all that =0

- anonymous

wht ? confused .

- anonymous

whts tht equation for .

- anonymous

kk wait

- anonymous

okay

- anonymous

\[ax ^{2} + bx + a =0 \]
where you plug is a b c in the quadratic equation
\[(-b \pm \sqrt{b ^{2}-4ac})/(2a)\]

- anonymous

to get to values

- anonymous

can you tell me the answer please .

- anonymous

in this case a=1 b=-3 a=5/4

- anonymous

umm just plug it in I gave you want to plug in

- anonymous

it didnt give me no answer

- anonymous

just plug in x =2, x = 2.5, x = -1 and x = 0.5 in the equation and see which value solves it. That will be your answer.

- anonymous

im still aint geting no answer something wrong

- anonymous

put x = 2 in \[x ^{2}-3x = -5/4\]

- anonymous

you will get \[2^{2}-3*2 = -5/4 => 4-6 = -5/4=>-2=-5/4\]

- anonymous

idk can i have the answer please .

- anonymous

-2 is obviously not equal to -5/4. so x = 2 is not the answer. similarly put x = 2.5, x = -1, x = 0.5 in the equation and see which one solve the equation

- anonymous

No, i can't do your problem for you. I can only show you how to do your problem

- anonymous

well , i dont know how to do this so . its only right if you do .

- anonymous

I showed you how to do it. just follow the steps.

- anonymous

rd can you tell me how to put it in the calculator .

- anonymous

Do you you know how to square things?\[X^2 \] ?

- anonymous

yess that = 1/2

- anonymous

no \[x^2 = x \times x\]

- anonymous

1/4

- anonymous

so just replace x with the given values and if the the equation makes sense then it works.

- anonymous

Do you know how to multiply and subtract?

- anonymous

yeaa

- anonymous

then just replace X with all the given values

- anonymous

and if the equation makes sense then thats one of the answers

- anonymous

so you sayinq 1/4 subtract all choices .

- anonymous

how did you get 1/4

- anonymous

1/2*1/2

- anonymous

well i got -1 thts the only answer i got

- anonymous

but its two answers

- anonymous

why is it two answers?

- anonymous

- 1 and 0.5

- anonymous

then you must have done some calculation wrong. Post what you got when you substituted x = 0.5

- anonymous

After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
A. http://media.apexlearning.com/Images/200712/03/a43220e6-97e8-4d20-a14d-11fd1ac1fc7f.gif
B. http://media.apexlearning.com/Images/200712/03/c11f4c31-5d7b-4b71-8c3f-bffb49e48fa7.gif
C. http://media.apexlearning.com/Images/200712/03/fd85edd2-763d-40eb-9ae8-7b626bdac1f0.gif
D. http://media.apexlearning.com/Images/200712/03/83c6b595-efe4-4961-beb5-3e724a260a21.gif

- anonymous

cant view pics, permission denied.

- radar

Your reluctance to substitute the answers from using the quadratic formula is discouraging. The two answers you should of gotten were 5/2, AND 1/2.
Substituting the 5/2 into your original formula would of resulted in:\[(5/2)^{2}-15/2+5/4=0\]
25/4-15/2+5/4=0
25/4-30/4+5/4=0
0=0 5/2 is a good answer. Now check out the 1/2

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