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anonymous
 5 years ago
A. x = 2
B. x = 2.5
C. x = 1
D. x = 0.5
anonymous
 5 years ago
A. x = 2 B. x = 2.5 C. x = 1 D. x = 0.5

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what's the question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^23x=5/4 Which choices are solutions to the following equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Have you tried using the quadratic equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is the quadratic:\[b \pm \sqrt{b ^{2}4ac}/2a\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry it didnt come out right http://en.wikipedia.org/wiki/Quadratic_equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no its going to be two values

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you first want to set the given equation =0 kk? How do you do that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whts tht equation for .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ax ^{2} + bx + a =0 \] where you plug is a b c in the quadratic equation \[(b \pm \sqrt{b ^{2}4ac})/(2a)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you tell me the answer please .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in this case a=1 b=3 a=5/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0umm just plug it in I gave you want to plug in

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it didnt give me no answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just plug in x =2, x = 2.5, x = 1 and x = 0.5 in the equation and see which value solves it. That will be your answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im still aint geting no answer something wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put x = 2 in \[x ^{2}3x = 5/4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you will get \[2^{2}3*2 = 5/4 => 46 = 5/4=>2=5/4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk can i have the answer please .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02 is obviously not equal to 5/4. so x = 2 is not the answer. similarly put x = 2.5, x = 1, x = 0.5 in the equation and see which one solve the equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, i can't do your problem for you. I can only show you how to do your problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well , i dont know how to do this so . its only right if you do .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I showed you how to do it. just follow the steps.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rd can you tell me how to put it in the calculator .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you you know how to square things?\[X^2 \] ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no \[x^2 = x \times x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so just replace x with the given values and if the the equation makes sense then it works.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how to multiply and subtract?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then just replace X with all the given values

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and if the equation makes sense then thats one of the answers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you sayinq 1/4 subtract all choices .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i got 1 thts the only answer i got

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why is it two answers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you must have done some calculation wrong. Post what you got when you substituted x = 0.5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0After being rearranged and simplified, which of the following equations could be solved using the quadratic formula? A. http://media.apexlearning.com/Images/200712/03/a43220e697e84d20a14d11fd1ac1fc7f.gif B. http://media.apexlearning.com/Images/200712/03/c11f4c315d7b4b718c3fbffb49e48fa7.gif C. http://media.apexlearning.com/Images/200712/03/fd85edd2763d40eb9ae87b626bdac1f0.gif D. http://media.apexlearning.com/Images/200712/03/83c6b595efe44961beb53e724a260a21.gif

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cant view pics, permission denied.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Your reluctance to substitute the answers from using the quadratic formula is discouraging. The two answers you should of gotten were 5/2, AND 1/2. Substituting the 5/2 into your original formula would of resulted in:\[(5/2)^{2}15/2+5/4=0\] 25/415/2+5/4=0 25/430/4+5/4=0 0=0 5/2 is a good answer. Now check out the 1/2
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