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anonymous 5 years ago Let f(x) =√(x+1.) compute the Taylor series around a=3 for the first three terms. Use this to estimate √(4.1.) What is the error?

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1. anonymous

$2+\frac{x-3}{4}-\frac{1}{64} (x-3)^2$ The series evaluated at 3.1 is 2.02484 $\sqrt{4.1} = 2.02485$ $\text{Error}: 1*10^{-5}$ Here is the series with an extra term if you need it. $2+\frac{x-3}{4}-\frac{1}{64} (x-3)^2+\frac{1}{512} (x-3)^3$

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