anonymous
  • anonymous
differentiate y=x/square root (x^2+1)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Use the quotient rule. Do you know what that is?
anonymous
  • anonymous
yes i just wanted to know the answer because i keep getting something different to the answer given
anonymous
  • anonymous
so i'm not sure where i went wrong

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anonymous
  • anonymous
What did you get?
anonymous
  • anonymous
1/(x^2+1)
anonymous
  • anonymous
I think you forgot -x
anonymous
  • anonymous
and the correct answer according to the solution is 1/(x^2+1)^(3/2)
anonymous
  • anonymous
I got \[(1/(x^2+1) )-x\]
anonymous
  • anonymous
The derivative is: \[-\frac{x^2}{\left(1+x^2\right)^{3/2}}+\frac{1}{\sqrt{1+x^2}}=\frac{1}{\left(1+x^2\right)^{3/2}} \]
anonymous
  • anonymous
robtobey could you show me your working out before reaching what you had come up with in the above post thanks!
anonymous
  • anonymous
Used Mathematica 8. The request for the derivative from that program was:\[D\left[\frac{x}{\sqrt{1+x^2}},x\right] \] Browse over to WolframAlpha.com and enter: derivative of x/square root (x^2+1) Seclect show steps See the attachment
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anonymous
  • anonymous
Product rule: \[ \dfrac{\mathbb{d}}{\mathbb{d}x}(u\cdot v)=u\cdot \dfrac{\mathbb{d}v}{\mathbb{d}x}+v\cdot \dfrac{\mathbb{d}u}{\mathbb{d}x} \] where u, v are functions of x. The quotient rule is just extra baggage.
anonymous
  • anonymous
thank you robtobey,romero and INewton!! ^.^
anonymous
  • anonymous
¬_¬ It was all robtobey.
anonymous
  • anonymous
but INewton made a lovely conclusion to the question!
anonymous
  • anonymous
=]

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