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anonymous

  • 5 years ago

differentiate y=x/square root (x^2+1)

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  1. anonymous
    • 5 years ago
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    Use the quotient rule. Do you know what that is?

  2. anonymous
    • 5 years ago
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    yes i just wanted to know the answer because i keep getting something different to the answer given

  3. anonymous
    • 5 years ago
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    so i'm not sure where i went wrong

  4. anonymous
    • 5 years ago
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    What did you get?

  5. anonymous
    • 5 years ago
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    1/(x^2+1)

  6. anonymous
    • 5 years ago
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    I think you forgot -x

  7. anonymous
    • 5 years ago
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    and the correct answer according to the solution is 1/(x^2+1)^(3/2)

  8. anonymous
    • 5 years ago
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    I got \[(1/(x^2+1) )-x\]

  9. anonymous
    • 5 years ago
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    The derivative is: \[-\frac{x^2}{\left(1+x^2\right)^{3/2}}+\frac{1}{\sqrt{1+x^2}}=\frac{1}{\left(1+x^2\right)^{3/2}} \]

  10. anonymous
    • 5 years ago
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    robtobey could you show me your working out before reaching what you had come up with in the above post thanks!

  11. anonymous
    • 5 years ago
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    Used Mathematica 8. The request for the derivative from that program was:\[D\left[\frac{x}{\sqrt{1+x^2}},x\right] \] Browse over to WolframAlpha.com and enter: derivative of x/square root (x^2+1) Seclect show steps See the attachment

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  12. anonymous
    • 5 years ago
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    Product rule: \[ \dfrac{\mathbb{d}}{\mathbb{d}x}(u\cdot v)=u\cdot \dfrac{\mathbb{d}v}{\mathbb{d}x}+v\cdot \dfrac{\mathbb{d}u}{\mathbb{d}x} \] where u, v are functions of x. The quotient rule is just extra baggage.

  13. anonymous
    • 5 years ago
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    thank you robtobey,romero and INewton!! ^.^

  14. anonymous
    • 5 years ago
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    ¬_¬ It was all robtobey.

  15. anonymous
    • 5 years ago
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    but INewton made a lovely conclusion to the question!

  16. anonymous
    • 5 years ago
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    =]

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