anonymous
  • anonymous
if f(x)=3x^2-2x-5, find(2u+1) can you explain how to work the problem and whats the answer i can get to f(2u+1)=3(2u+1) after that i don't know
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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radar
  • radar
\[f(2u+1)=3(2u+1)^{2}-2(2u+1)-5\] Thats a start.
radar
  • radar
\[=3(4u ^{2}+4u+1)-4u-2-5\] just keep on trucking!
radar
  • radar
Earth to shrryflores, do you follow so far?

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More answers

anonymous
  • anonymous
yes
radar
  • radar
Let's continue then: \[12u ^{2}+12u+3-4u-7\] \[12u ^{2}+8u+4\]
radar
  • radar
change that +4 to -4
anonymous
  • anonymous
ok it makes since
radar
  • radar
since there was no = sign I think that is as far as needed\[12u ^{2}+12u-4\]
radar
  • radar
\[f(2u+1)=12u ^{2}+12u-4\]
anonymous
  • anonymous
\[f(2u+1)=12u^2+8u-4\] You can find the roots of u using the quadratic formula: \[u=-\frac{1}{3}\pm \frac{2}{3}\rightarrow u=-1, u=\frac{1}{3}\]
radar
  • radar
I was wondering if it was to be taken any further? Couldn't determine if they were wanting the roots.
anonymous
  • anonymous
I gave the roots just in case
radar
  • radar
Fine business, they say "whats the answer" maybe that was what they wanted. thanks and good luck to you and shrryflores

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