if f(x)=3x^2-2x-5, find(2u+1) can you explain how to work the problem and whats the answer i can get to f(2u+1)=3(2u+1) after that i don't know

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if f(x)=3x^2-2x-5, find(2u+1) can you explain how to work the problem and whats the answer i can get to f(2u+1)=3(2u+1) after that i don't know

Mathematics
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\[f(2u+1)=3(2u+1)^{2}-2(2u+1)-5\] Thats a start.
\[=3(4u ^{2}+4u+1)-4u-2-5\] just keep on trucking!
Earth to shrryflores, do you follow so far?

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Other answers:

yes
Let's continue then: \[12u ^{2}+12u+3-4u-7\] \[12u ^{2}+8u+4\]
change that +4 to -4
ok it makes since
since there was no = sign I think that is as far as needed\[12u ^{2}+12u-4\]
\[f(2u+1)=12u ^{2}+12u-4\]
\[f(2u+1)=12u^2+8u-4\] You can find the roots of u using the quadratic formula: \[u=-\frac{1}{3}\pm \frac{2}{3}\rightarrow u=-1, u=\frac{1}{3}\]
I was wondering if it was to be taken any further? Couldn't determine if they were wanting the roots.
I gave the roots just in case
Fine business, they say "whats the answer" maybe that was what they wanted. thanks and good luck to you and shrryflores

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