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anonymous

  • 5 years ago

Can someone help with 7th grade algebra? i understand, but i still need help

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  1. anonymous
    • 5 years ago
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    sure

  2. anonymous
    • 5 years ago
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    thanks. variables and percentages are difficult fot me

  3. anonymous
    • 5 years ago
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    have u got any question with u ?

  4. anonymous
    • 5 years ago
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    no, im sorry

  5. anonymous
    • 5 years ago
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    Then how am I supposed to exlain...if do not have any questions

  6. anonymous
    • 5 years ago
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    i do! can't you just make up a problem? gooses >:(

  7. anonymous
    • 5 years ago
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    ok

  8. anonymous
    • 5 years ago
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    thanks

  9. anonymous
    • 5 years ago
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    x + 5 = 6 ... something like this?

  10. anonymous
    • 5 years ago
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    yeah. that would be 1. right?

  11. anonymous
    • 5 years ago
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    ok... we need to solve for x...for this we have to subtract anything which is on left side...in this case we have 5 ... so x +5 - 5 = 6 -5 ... u got it?

  12. anonymous
    • 5 years ago
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    i think so?

  13. anonymous
    • 5 years ago
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    :(

  14. anonymous
    • 5 years ago
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    ok, so i just thought that you went like "Ok, so it is x + 5 = 6, so i can flip it around, to where it makes 6 - 5 = x, and the answer would be one" thats just how i think :/

  15. anonymous
    • 5 years ago
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    ok so are you doing Pre-algebra? is tht wat ur school calls it?

  16. anonymous
    • 5 years ago
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    yes.... i'm trying to get to just plain algebra too because i am really slow when it comes to math

  17. anonymous
    • 5 years ago
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    ya same here but i rocked it when i took pre agebra all A's All year. idk why... anyways so u say u dont have a problem but im in a much bigger math class than that right now so i cant make up a problem.... so u give me one and i can help!

  18. anonymous
    • 5 years ago
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    um ok.... say if it was like 4t - 6 = 27 ¿:ı somethin like that. i will brb i need to go make some food... it will take like one minute

  19. anonymous
    • 5 years ago
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    ok imma rite the steps the solve that problem it EASY

  20. anonymous
    • 5 years ago
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    k back

  21. anonymous
    • 5 years ago
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    so the problem is 4t - 6 = 27 and ur trying to find the value of T. The first step is: 4t - 6 = 27 +6 +6 4t = 27 + 6 ^ 33 4t = 33 4 4 The fours cancel out so that t = 33 / 4 ^ t = 8.25 Get it kinda?

  22. anonymous
    • 5 years ago
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    uh...

  23. anonymous
    • 5 years ago
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    ?

  24. anonymous
    • 5 years ago
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    whats thr +6 +6 thinggy?

  25. anonymous
    • 5 years ago
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    thats just a step u need to do so that you can find what t equals. Bc 4T - 6 = 27 so that to find t u have to find oh well nvm

  26. anonymous
    • 5 years ago
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    i'm sorry

  27. anonymous
    • 5 years ago
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    i'm stupid :/ i suck at ,ath

  28. awhite
    • 5 years ago
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    basically if you have b+2=3 and you want to solve to b, to get rid of the 2 on the right hand side of the ='s sign, you have to subtract 2 from both sides of the equation. so you have: b+2-2 = 3-2 b+0 = 3-2 = 1 so b=1

  29. anonymous
    • 5 years ago
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    that makes some sense

  30. awhite
    • 5 years ago
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    basically whatever you do to one side of the equation, you have to also do to the other side

  31. awhite
    • 5 years ago
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    so if you have 2*a = 10 and you need to solve for a then you need to divide both sides by 2 to get rid of the 2 multiplying the a, and you end up with 2*a/2 = 10/2 = 5 so a = 5

  32. anonymous
    • 5 years ago
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    ¿:ı i understnad most of that

  33. awhite
    • 5 years ago
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    so could you solve for c in: 2*v +3 = 23 ?

  34. awhite
    • 5 years ago
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    sorry solve for v!

  35. anonymous
    • 5 years ago
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    um yes.. so .... uhh

  36. awhite
    • 5 years ago
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    where do you think you'd start?

  37. anonymous
    • 5 years ago
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    at the 2*v right? can you turn it around?

  38. awhite
    • 5 years ago
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    It would be easier to start by getting rid of the 3 on the right hand side.

  39. anonymous
    • 5 years ago
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    ok. so, because it is a positive you would subtract right?

  40. awhite
    • 5 years ago
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    yep

  41. anonymous
    • 5 years ago
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    so, 2*v +3- 3 = 23 ?

  42. awhite
    • 5 years ago
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    subtract from both sides :)

  43. anonymous
    • 5 years ago
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    oh yeah :) 2*v +3- 3 = 23- 3 would = 20 so far right?

  44. awhite
    • 5 years ago
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    yep

  45. anonymous
    • 5 years ago
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    k so what would you do next?

  46. awhite
    • 5 years ago
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    well then as you have 2*v = 20, you want to get rid of the 2

  47. anonymous
    • 5 years ago
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    um would you do the same thing? but ddividing?

  48. awhite
    • 5 years ago
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    exactly. divide through on both sides.

  49. anonymous
    • 5 years ago
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    k so... i'm sorry i suck at division. whatt would you divide by?

  50. awhite
    • 5 years ago
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    so because you want to get rid of the 2, you divide through by 2. ie: 2*v/2 = 20/2

  51. awhite
    • 5 years ago
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    does that make sense?

  52. anonymous
    • 5 years ago
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    yes.. but why would you keep the *v ?

  53. anonymous
    • 5 years ago
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    i'm sorry :/

  54. awhite
    • 5 years ago
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    you are solving for v, so you want to end up with v on one side, and everything else on the other side of the equation.

  55. anonymous
    • 5 years ago
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    oh. so... you would end up with 1 right? but on the right side it would be 10.

  56. awhite
    • 5 years ago
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    yeah, because v*1 = v :) so v = 10 is the answer

  57. anonymous
    • 5 years ago
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    sweet! thanks (:

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