Find the volume in the first octant bounded by the coordinate planes, y=4, the plane (x/3) +(z/5) =1.

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Find the volume in the first octant bounded by the coordinate planes, y=4, the plane (x/3) +(z/5) =1.

Mathematics
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Double integral problem
Y end points is 0 to 4, I can solve for z to find the top what about x?
My guess would be since we are talking about the first octant that all values have to be positive, x goes from 0 to 3 -> z = 5-(5/3)x z bounded from 0 to 5 ->x = 3 - (3/5)z x bounded from 0 to 3

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How did you determine x?
i might be oversimplifying this but it seems that this forms a right triangular prism where actually you could do it without integrals V = (1/2)*5*3*4 = 30 If im mistaken i apologize
I understand. It is an exercise: they are trying to teach us how to set up double integrals.
oh ok To determine x look at the linear relationship between z and x, x has to be between 0 and 3 for z to be positive
thanks, i'll take a closer look

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