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anonymous
 5 years ago
simple exponential equations problem!
determine the exact value of x
3^(2x)= 5(3^x)+ 36
anonymous
 5 years ago
simple exponential equations problem! determine the exact value of x 3^(2x)= 5(3^x)+ 36

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0treat it like a quadratic u = 3^x _>u^25u36 = 0 Factor and solve for u Then replace u with 3^x and solve for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so i factored and go (u9)(u+4).. i dont really understand what to do next!

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0good solve each part separately u9 =0 u+4=0

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0which means 3^x = 9 and 3^x = 4 Find x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the left side of the equation is 3^(2x), not 3^x...

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0correct but took care of that part when we made it a quadratic 3^2x became u^2 dont worry its the same x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so for 3^x=9, x = 2 but i dont know how to do it for the other one

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0good actually the one doesnt exist 3^x > 0

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0graph it to see for yourself

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0there is only one answer of 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok awesome! thank you sososo much!
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