anonymous
  • anonymous
simple exponential equations problem! determine the exact value of x 3^(2x)= 5(3^x)+ 36
Mathematics
jamiebookeater
  • jamiebookeater
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dumbcow
  • dumbcow
treat it like a quadratic u = 3^x _>u^2-5u-36 = 0 Factor and solve for u Then replace u with 3^x and solve for x
anonymous
  • anonymous
ok so i factored and go (u-9)(u+4).. i dont really understand what to do next!
dumbcow
  • dumbcow
good solve each part separately u-9 =0 u+4=0

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anonymous
  • anonymous
ok, so u=9 and -4
dumbcow
  • dumbcow
which means 3^x = 9 and 3^x = -4 Find x
anonymous
  • anonymous
but the left side of the equation is 3^(2x), not 3^x...
dumbcow
  • dumbcow
correct but took care of that part when we made it a quadratic 3^2x became u^2 dont worry its the same x
anonymous
  • anonymous
ok so for 3^x=9, x = 2 but i dont know how to do it for the other one
dumbcow
  • dumbcow
good actually the one doesnt exist 3^x > 0
dumbcow
  • dumbcow
graph it to see for yourself
dumbcow
  • dumbcow
there is only one answer of 2
anonymous
  • anonymous
ok awesome! thank you sososo much!
dumbcow
  • dumbcow
welcome

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