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anonymous

  • 5 years ago

simple exponential equations problem! determine the exact value of x 3^(2x)= 5(3^x)+ 36

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  1. dumbcow
    • 5 years ago
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    treat it like a quadratic u = 3^x _>u^2-5u-36 = 0 Factor and solve for u Then replace u with 3^x and solve for x

  2. anonymous
    • 5 years ago
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    ok so i factored and go (u-9)(u+4).. i dont really understand what to do next!

  3. dumbcow
    • 5 years ago
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    good solve each part separately u-9 =0 u+4=0

  4. anonymous
    • 5 years ago
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    ok, so u=9 and -4

  5. dumbcow
    • 5 years ago
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    which means 3^x = 9 and 3^x = -4 Find x

  6. anonymous
    • 5 years ago
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    but the left side of the equation is 3^(2x), not 3^x...

  7. dumbcow
    • 5 years ago
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    correct but took care of that part when we made it a quadratic 3^2x became u^2 dont worry its the same x

  8. anonymous
    • 5 years ago
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    ok so for 3^x=9, x = 2 but i dont know how to do it for the other one

  9. dumbcow
    • 5 years ago
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    good actually the one doesnt exist 3^x > 0

  10. dumbcow
    • 5 years ago
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    graph it to see for yourself

  11. dumbcow
    • 5 years ago
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    there is only one answer of 2

  12. anonymous
    • 5 years ago
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    ok awesome! thank you sososo much!

  13. dumbcow
    • 5 years ago
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    welcome

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