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anonymous

  • 5 years ago

simple exponential equation help! solve (without using logs) 3(^2x+1)=70

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  1. dumbcow
    • 5 years ago
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    i get x = 1.43 but i used logs so it doesnt count

  2. dumbcow
    • 5 years ago
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    why cant you use logs

  3. anonymous
    • 5 years ago
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    how do you do it with logs then?

  4. anonymous
    • 5 years ago
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    haha i was already excited what the solution is xD

  5. anonymous
    • 5 years ago
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    well it's grade 11 functions and apps, and logs is apparently advanced functions so she doesnt want us using them. but whatever, i'll use logs.

  6. dumbcow
    • 5 years ago
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    take log base 3 of both sides ->2x+1 = log3(70) get x by itself _>2x = log3(70) -1 ->x = (1/2)*(log3(70)-1) use change of base formula to find log3(70)

  7. dumbcow
    • 5 years ago
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    log3(70) = log(70)/log(3) sorry you prob didnt know what i meant

  8. dumbcow
    • 5 years ago
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    wait sorry i think i know what your teacher wanted 3^2x+1 = 3^2x*3^1 = 70 divide 3 on both sides 3^2x = 70/3 square root both sides 3^x = sqrt(70/3) = 4.83 then estimate your best guess for x

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