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anonymous
 5 years ago
simple exponential equation help!
solve (without using logs)
3(^2x+1)=70
anonymous
 5 years ago
simple exponential equation help! solve (without using logs) 3(^2x+1)=70

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0i get x = 1.43 but i used logs so it doesnt count

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you do it with logs then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha i was already excited what the solution is xD

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well it's grade 11 functions and apps, and logs is apparently advanced functions so she doesnt want us using them. but whatever, i'll use logs.

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0take log base 3 of both sides >2x+1 = log3(70) get x by itself _>2x = log3(70) 1 >x = (1/2)*(log3(70)1) use change of base formula to find log3(70)

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0log3(70) = log(70)/log(3) sorry you prob didnt know what i meant

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0wait sorry i think i know what your teacher wanted 3^2x+1 = 3^2x*3^1 = 70 divide 3 on both sides 3^2x = 70/3 square root both sides 3^x = sqrt(70/3) = 4.83 then estimate your best guess for x
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