anonymous
  • anonymous
simple exponential equation help! solve (without using logs) 3(^2x+1)=70
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
dumbcow
  • dumbcow
i get x = 1.43 but i used logs so it doesnt count
dumbcow
  • dumbcow
why cant you use logs
anonymous
  • anonymous
how do you do it with logs then?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
haha i was already excited what the solution is xD
anonymous
  • anonymous
well it's grade 11 functions and apps, and logs is apparently advanced functions so she doesnt want us using them. but whatever, i'll use logs.
dumbcow
  • dumbcow
take log base 3 of both sides ->2x+1 = log3(70) get x by itself _>2x = log3(70) -1 ->x = (1/2)*(log3(70)-1) use change of base formula to find log3(70)
dumbcow
  • dumbcow
log3(70) = log(70)/log(3) sorry you prob didnt know what i meant
dumbcow
  • dumbcow
wait sorry i think i know what your teacher wanted 3^2x+1 = 3^2x*3^1 = 70 divide 3 on both sides 3^2x = 70/3 square root both sides 3^x = sqrt(70/3) = 4.83 then estimate your best guess for x

Looking for something else?

Not the answer you are looking for? Search for more explanations.