anonymous
  • anonymous
simple exponential equation help! solve (without using logs) 3(^2x+1)=70
Mathematics
jamiebookeater
  • jamiebookeater
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dumbcow
  • dumbcow
i get x = 1.43 but i used logs so it doesnt count
dumbcow
  • dumbcow
why cant you use logs
anonymous
  • anonymous
how do you do it with logs then?

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anonymous
  • anonymous
haha i was already excited what the solution is xD
anonymous
  • anonymous
well it's grade 11 functions and apps, and logs is apparently advanced functions so she doesnt want us using them. but whatever, i'll use logs.
dumbcow
  • dumbcow
take log base 3 of both sides ->2x+1 = log3(70) get x by itself _>2x = log3(70) -1 ->x = (1/2)*(log3(70)-1) use change of base formula to find log3(70)
dumbcow
  • dumbcow
log3(70) = log(70)/log(3) sorry you prob didnt know what i meant
dumbcow
  • dumbcow
wait sorry i think i know what your teacher wanted 3^2x+1 = 3^2x*3^1 = 70 divide 3 on both sides 3^2x = 70/3 square root both sides 3^x = sqrt(70/3) = 4.83 then estimate your best guess for x

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