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anonymous
 5 years ago
A club with 33 members is to select five officers (president, vice president, secretary, treasurer, and historian). In how many ways can this be done?
anonymous
 5 years ago
A club with 33 members is to select five officers (president, vice president, secretary, treasurer, and historian). In how many ways can this be done?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry incorrect, that is only right if one member can hold all the positions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol sorry, thats why i need help too :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0otherwise u need to account for the loss of options as each position is filled, so it would be 35 + 34 +33 +32 +31

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry make those multiplication signs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is a certain formula set up for this but i have hard time remembering which one i think it is the nCr one if u know what that is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if the question is, how many ways 5 people can be chosen from 33, it's n choose k, or 33 choose 5, or 33!/(5!(335)!), if you have to factor in the positions, multiply that by how many ways you can arrange 5 people, cards, whatever, 5!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if that wasn't clear, permutation (what position each person has matters) is 33!/(335)!, combination (position doesn't matter) is 33!/((335)!5!)
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