anonymous
  • anonymous
the sume of three consecutive odd integers if five less than twice the smallest of these integers. Find the smallest of these integers and find the greatest of these integers.??
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
radar
  • radar
let 2x+1 = first odd integer let 2x+3 = 2nd odd integer let 2x+5 = 3rd odd integer Sum = 2x+1+2x+3+2x=5=6x+9 Problem stated that the sum is 5 less than twice the smallest of these integers. Sum = 2(2x+1) - 5. write the equation 6x + 9 = 2(2x+1)-5 6x+ 9 = 4x +2 -5 6x-4x=-12 2x = -12 x=-6 first odd integer =-12+1 = -11 2nd odd integer =-12+3 = -9 3rd odd integer =-12 +5= -7 The smallest of these integers is -11 The sum of these integers is -27 which is 5 less than twice -11 or-22

Looking for something else?

Not the answer you are looking for? Search for more explanations.